Lithium is in group 1 of the Periodic Table, so it must lose one electron in order to attain a full outer energy level and become stable.
To calculate the amount of lithium nitrate needed to make lithium sulfate, first determine the molar masses of the two compounds. Then, use stoichiometry and the balanced chemical equation for the reaction between lithium nitrate and lithium sulfate to find the quantity needed. This will depend on the stoichiometry of the reaction between lithium nitrate and lithium sulfate.
Lithium's small size and high charge density make it more likely to form stable ionic compounds rather than covalent compounds like acetylides. Sodium, with a larger size and lower charge density, is more likely to form covalent bonds, allowing it to form acetylides.
For the water molecule (H2O) two hydrogen atoms are needed.
Lithium does not have a '0' charge. Its electron configuration is 2,1. This means there is one valence electron in its outer shell. Losing this electron will make Lithium have a full shell (2 only) which all atoms try to achieve, therefore Li has a +1 charge because it loses an electron to gain noble gas configuration.
The bond in lithium fluoride is ionic and the compound is polar.The crystalline structure is face-cenered cubic.
fluoride is used with lithium
Lithium
To calculate the amount of lithium nitrate needed to make lithium sulfate, first determine the molar masses of the two compounds. Then, use stoichiometry and the balanced chemical equation for the reaction between lithium nitrate and lithium sulfate to find the quantity needed. This will depend on the stoichiometry of the reaction between lithium nitrate and lithium sulfate.
To determine the number of grams of lithium nitrate needed to make 250 grams of lithium sulfate, you need to calculate the molar mass of lithium sulfate and lithium nitrate, then use stoichiometry to find the ratio of lithium nitrate to lithium sulfate. Finally, apply this ratio to find the mass of lithium nitrate needed for the reaction. Lead sulfate is not involved in this calculation as it is not part of the reaction between lithium nitrate and lithium sulfate.
The oxidation number for Li, or Lithium, is Li+1. Lithium is in the first family on the Periodic Table. Since the element wants to become stable, and it only it needs 8 valence electrons. So therefore, it has to lose an electron. Losing an electron will make it a positive oxidation number.
Only 1 electron needed to make H stable.
To find out the grams of lithium nitrate needed, you need to calculate the molar mass of lithium sulfate (Li2SO4) and lithium nitrate (LiNO3). Then use stoichiometry to determine the amount of lithium nitrate required to produce 250 grams of lithium sulfate. The balanced chemical equation for the reaction would also be needed.
Lithium is an element itself, it is simply Li. Nitrate is Nitrogen and Oxygen, the -ate ending denoting an oxide ion!
That is the element, "Oxygen".
If you just say lithium, it's probable you are referring to an atom. Lithium however can form an ion, Li+ (where the + should be a superscript). Without knowing the context it is not possible to give a definitive answer.
You must make it stable if it is unstable it will oxidise by definition. You would have to add another element to make the compound stable but you would then be changing it to a stable salt.
There are too many electrons. This would be a negative ion of lithium-6 (stable but less common isotope) that does not occur naturally. The element with 3 electrons, 3 protons, and *4 neutrons* is lithium-7, the most common isotope. It forms a stable positive ion (2 electrons).