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How many grams of barium chloride are needed to make 100. grams of barium sulfate?
89.3
How many grams of HCl are needed to make 21.5 grams of Na2SO4?
Sodium sulfate is not prepared from hydrogen chloride.
What mass of silver nitrate is needed to fully react with 10.0 grams of calcium chloride?
The mass of silver nitrate is 30,6 g.
Which has the greatest number of atoms- 3.5 grams of helium or 3.5 grams of lithium?
3.5 grams of lithium would have a greater number of atoms because lithium is heavier than helium. Each element has a different atomic mass, so the same weight of each element will contain a different number of atoms.
How many grams of barium sulfate can be produced from 20.8 grams of barium sulfate?
If you start with 20.8 grams of barium sulfate (BaSO₄), you cannot produce more barium sulfate from it; you can only measure how much you have. Therefore, you can produce a maximum of 20.8 grams of barium sulfate if you are referring to using the same amount of BaSO₄ in a reaction or process. In summary, you have 20.8 grams of barium sulfate available, not more.
How many grams of lithium nitrate will be needed to make 250 grams of lithium sulfate assuming that you have an adequate amount of lead sulfate to do the reaction?
To determine the number of grams of lithium nitrate needed to make 250 grams of lithium sulfate, you need to calculate the molar mass of lithium sulfate and lithium nitrate, then use stoichiometry to find the ratio of lithium nitrate to lithium sulfate. Finally, apply this ratio to find the mass of lithium nitrate needed for the reaction. Lead sulfate is not involved in this calculation as it is not part of the reaction between lithium nitrate and lithium sulfate.
How many grams of lithium nirate will be needed to make 250 grams of lithium sulfate assuming that you have an adequate amount of lead sulfate to do the reaction?
To find out the grams of lithium nitrate needed, you need to calculate the molar mass of lithium sulfate (Li2SO4) and lithium nitrate (LiNO3). Then use stoichiometry to determine the amount of lithium nitrate required to produce 250 grams of lithium sulfate. The balanced chemical equation for the reaction would also be needed.
What is the molar mass of lithium sulfate?
Molecular weight calculation: 6.941*2 + 32.065 + 15.9994*4
How many grams of silver nitrate are needed to react with 50 grams of sodium chloride?
You need 145,337 g silver nitrate.
Molarity of 734 grams of lithium sulfate are dissolved to make 2500ml of solution?
To find the molarity of the solution, first calculate the number of moles of lithium sulfate in 734g. Then, divide the moles by the volume of solution in liters to get the molarity. Remember to convert grams to moles using the molar mass of lithium sulfate (Li2SO4).
How many grams of barium chloride are needed to make 100. grams of barium sulfate?
89.3
How many grams of silver nitrate is needed to make 275ml of a 0.567m sollution of silver nitrate?
You need 26,49 g silver nitrate.
How many grams of sodium sulfate Na's must be added to make 500 ml of M sodium sulfate solution?
To determine the grams of sodium sulfate needed, you first need to specify the molarity (M) of the sodium sulfate solution. Once you have the molarity, you can use the formula: grams = molarity (M) x volume (L) x molar mass (g/mol). This will give you the amount of sodium sulfate in grams needed to make the solution.
How many grams of HCl are needed to make 21.5 grams of Na2SO4?
Sodium sulfate is not prepared from hydrogen chloride.
What mass of silver nitrate is needed to fully react with 10.0 grams of calcium chloride?
The mass of silver nitrate is 30,6 g.
How many grams of barium chloride are needed to make 100 grams of barium sulfate?
Since barium sulfate and barium chloride have a 1:1 molar ratio, you would need the same amount of barium chloride as barium sulfate, so 100 grams.
How many grams of aluminum is required to produce 25.0 grams of aluminum sulfate?
To find the amount of aluminum needed to produce aluminum sulfate, you need to consider the molar mass of aluminum sulfate and the ratio of aluminum in the compound. First, calculate the molar mass of aluminum sulfate (Al2(SO4)3). Then, find the ratio of aluminum in the compound (2 moles of Al in 1 mole of Al2(SO4)3). Finally, use this information to calculate the grams of aluminum needed to produce 25.0 grams of aluminum sulfate.
