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Explains why a balloon bulges on one end when you pinch the other end?
The first part of the explanation is understanding why a balloon changes when you put air into it. Before you blow up a balloon, you can see that the volume is small and that the balloon is elastic. As you put more air into the balloon you are increasing the pressure. The air is packed in tight, so it attempts to push out and escape, so the balloon's surface stretches until a balance is reached. The tension of the balloon's surface combined with the outside atmosphere's pressure matches the internal pressure of the air. This equilibrium is always held. If you increase the pressure (putting more air into the balloon) the balloon's surface gives just enough so that you equilibrium is reached again. It is this maintaining of equilibrium that answers your question. If you try and decrease the volume in one area of the balloon, the air is going to push out another area of the balloon to make up for the lost volume. The volume is always maintained and the pressure remains constant.
How much will the pressure increase for one cubic meter of air when heated by one degree c?
it'll increase by alot
Why does a balloon expand until the pressure of the gas inside balloon balances the pressure of the gas outside?
In a closed container where air or other gases tend to occupy space, there is the presence of air pressure that does an upward force. This force exerted inside the balloon able the balloon to fly, but there is an opposing force outside it, which is also air pressures. Hence, the air pressure inside the balloon must be greater than the air pressure outside it, for the balloon to be lifted up. I'm not sure this guy ^ answered your question or not. Actually, it's completely wrong. If you ARE talking about helium balloons, as he seemed to be, then Helium is a lighter gas than the combined gases in the air. Just like mixing olive oil and water, denser objects sink, and lighter objects float. Therefore, a helium balloon will float upwards until it pops. If you WEREN'T talking about helium balloons, which I don't think you were, then you're like me. I've been doing some research to prove my theory. While hard to find, it seems to be pretty common knowledge in science (and yet, for some reason, my teacher was wrong about it - hence me doing outside research) that a balloon has a greater air pressure inside the wall than that outside. Air pressure, technically, is a measurement of the amount of collisions against a surface at any time. In the case of balloon, it's supposed to measure how many particles at any in any given time space collide with the wall of the balloon and bounce off. However, since this is near impossible to measure, air pressure seems to be easier described as density. The similarity comes from the idea that when there are more molecules in the same space, more of them will be heading towards a collision course with the wall. The first concept of air pressure within a balloon that you will need to know is that air pressures "try" to even out. With all the bouncing against the balloon wall (both in and out) there will be a certain amount of expansion/contraction. As air pressure itself is a description of the total forces against an object, each of these forces, on the outside of the balloon, causes the balloon to contract a tiny bit, while the inside forces cause the balloon to expand. With this knowledge, one would immediately assume the a balloon with high air pressure inside would expand based on the high amount of internal forces, and vice versa. This would make the inside and outside air pressures equal. However, the part I am looking for, that my science teacher doesn't agree with, is the fact that we are, after all, talking about balloons. Balloons have a certain elasticity to them that some won't take into account. When you stretch a balloon, you're filling it with potential energy. When you let it go, the potential energy is turned into kinetic energy and the balloon snaps back into its original position (though perhaps a little stretched out). When you fill up a balloon with air, the balloon is being stretched. While the balloon is constantly releasing kinetic energy in an attempt to contract, it is also being pushed back out by the constant bouncing of the internal air molecules. Because I'm still researching this, I'm not an expert, but basically, the internal air has to exert force not only to counteract the external air to keep the air pressures "even," but it also has to counteract the natural contraction of the balloon. Therefore, it requires more air pressure (more force) than the air outside the balloon wall. ________________________________________________________________ the gas pressure inside an inflated balloon always greater than the air pressure outside because as the atoms and molecules move about they hit the wall of the balloons which increases their speed so the gas pressure is higher then outside. The air pressure outside the wall is less because atoms and molecules can easily move about. When most of the atoms and molecules escape from the balloon the air becomes same outside and inside. ________________________________________________________________ Okay, no, that ^ just doesn't make any sense. Hitting the balloon wall does not increase speed. Also, the air outside the balloon is generally confined too. It is bouncing off the balloon, all of the objects in it's area, possibly walls and a ceiling... And, according to your theory, if air is let out, what's left would still have a greater pressure, because it's still hitting the walls...not that this 'theory' makes any sense...
If you push on the sides of a filled balloon how does the pressure inside change?
If the balloon is not encased or in restricted volume, then it changes its shape to accomodate that push but prutruding on the other side and the pressure remain same. However, if there is restriction for shape change, then when you push on the balloon, the volume decreases and therefore the pressure increases. A practical balloon, by the way, will behave between these two extremes. Pushing on one side and causing it to change shape definitely results in an increase in internal pressure. This is because the elasticity/tension of the rubber is the encased space.
Why an inflated balloon shoots off when its air is released?
To understand why balloons produce a bang, we must fist understand why they burst.As balloons reach their maximum expansion, they get to a point where the latex cannot stretch anymore and gets stiff and resists any further stretching. This increase in stiffness will cause an increase in the air pressure inside the balloon just before bursting.While the air pressure inside the balloon does not contain much potential energy, the latex does store terrific potential energy. The rapid release of the stored energy during the burst produces the resounding bang. More detailed explanationWhen a balloon bursts, the latex splits into various pieces as cracks are developed. The speed of sound in the latex is much higher than the speed of sound in air. The speed of the crack propagation through the latex approaches the speed of sound in the latex. Therefore, the velocity of the crack-faces breaks the sound barrier in air and produces a sonic boom. The latex then violently contracts. The ends of the latex contract so rapidly that they break the sound barrier.Just like the end of a bull-whip, they create a shock wave.More the latex breaking the sound barrier, the bigger the bang. The faster the latex is going, the bigger the bang.(check the related link for a video)
What explains why a balloon bulges on one end when you pinch the other end?
The first part of the explanation is understanding why a balloon changes when you put air into it. Before you blow up a balloon, you can see that the volume is small and that the balloon is elastic. As you put more air into the balloon you are increasing the pressure. The air is packed in tight, so it attempts to push out and escape, so the balloon's surface stretches until a balance is reached. The tension of the balloon's surface combined with the outside atmosphere's pressure matches the internal pressure of the air. This equilibrium is always held. If you increase the pressure (putting more air into the balloon) the balloon's surface gives just enough so that you equilibrium is reached again. It is this maintaining of equilibrium that answers your question. If you try and decrease the volume in one area of the balloon, the air is going to push out another area of the balloon to make up for the lost volume. The volume is always maintained and the pressure remains constant.
Explains why a balloon bulges on one end when you pinch the other end?
The first part of the explanation is understanding why a balloon changes when you put air into it. Before you blow up a balloon, you can see that the volume is small and that the balloon is elastic. As you put more air into the balloon you are increasing the pressure. The air is packed in tight, so it attempts to push out and escape, so the balloon's surface stretches until a balance is reached. The tension of the balloon's surface combined with the outside atmosphere's pressure matches the internal pressure of the air. This equilibrium is always held. If you increase the pressure (putting more air into the balloon) the balloon's surface gives just enough so that you equilibrium is reached again. It is this maintaining of equilibrium that answers your question. If you try and decrease the volume in one area of the balloon, the air is going to push out another area of the balloon to make up for the lost volume. The volume is always maintained and the pressure remains constant.
What change in pressure occurs in a party balloon that is squeezed to one-third its volume with no change in temperature?
The pressure will increase 3 fold
Which one of the following situations would cause air pressure to rise an increase in temperature cold air entering the region moisture entering the air?
Neither. The increase in altitude would cause air pressure to rise. :)
How much will the pressure increase for one cubic meter of air when heated by one degree c?
it'll increase by alot
Why does a balloon pop when stepped on?
It depends upon the strength of the rubber making up the balloon and how much air is already in it, which will increase pressure in certain regions of balloon when stepped on. The assumption is the one is stepping on the balloon with a wide shoe bottom, rather than a stiletto heel. Sometimes, you can step on a balloon, and the part under the foot gets flattened as the air gets displaced into the stretching parts of the balloon coming out from under the sides of the foot. If the air content is low enough to not overcome the tensile strength of the rubber, then the balloon will not pop. However, if there is enough air in the balloon to overcome the tensile strength of the rubber as the air pressure increases when you step on the balloon, then the balloon will pop. What happens is the part of the balloon under the foot remains still, and the air is forced away from that region, placing more air pressure on the rest of the balloon. This stretches the balloon so that it comes out the sides of the foot. In these regions, the air pressure is much greater. Now, due to the special intermolecular bonds in rubber, the molecules can remain bound but still stretch and bend, allowing for rubber to stretch. As air pressure builds, it produces a force against the inside of the rubber, causing the rubber to stretch. If the rubber stretches past the point where the molecules separate enough to form a small tear (air hole) in the rubber, then the overall forces placed on the rubber cause a VERY rapid failure in the adjacent regions of the rubber to maintain integrity. They rip, and the rubber next to it rips, and so forth in what is called cascade failure. In all, a large rip forms along the rubber as the air escapes its container (the balloon).
Why does a balloon pop when it stepped on?
It depends upon the strength of the rubber making up the balloon and how much air is already in it, which will increase pressure in certain regions of balloon when stepped on. The assumption is the one is stepping on the balloon with a wide shoe bottom, rather than a stiletto heel. Sometimes, you can step on a balloon, and the part under the foot gets flattened as the air gets displaced into the stretching parts of the balloon coming out from under the sides of the foot. If the air content is low enough to not overcome the tensile strength of the rubber, then the balloon will not pop. However, if there is enough air in the balloon to overcome the tensile strength of the rubber as the air pressure increases when you step on the balloon, then the balloon will pop. What happens is the part of the balloon under the foot remains still, and the air is forced away from that region, placing more air pressure on the rest of the balloon. This stretches the balloon so that it comes out the sides of the foot. In these regions, the air pressure is much greater. Now, due to the special intermolecular bonds in rubber, the molecules can remain bound but still stretch and bend, allowing for rubber to stretch. As air pressure builds, it produces a force against the inside of the rubber, causing the rubber to stretch. If the rubber stretches past the point where the molecules separate enough to form a small tear (air hole) in the rubber, then the overall forces placed on the rubber cause a VERY rapid failure in the adjacent regions of the rubber to maintain integrity. They rip, and the rubber next to it rips, and so forth in what is called cascade failure. In all, a large rip forms along the rubber as the air escapes its container (the balloon).
How is possible for one tank of helium to fill 700 balloon?
Helium is stored under pressure, so a lot is packed into a small space. The gas in the balloon is at only slightly more than normal air pressure. The helium spreads out as it fills the balloons.
Real life application for charle's law?
· The Ping-Pong BallsLittle children come up with ingenious ways of mending their toys. One of them is removing the dent from a ping-pong ball.When a ping-pong ball gets dented without being punctured, the best solution is to dip it for a while in warm water. Since the air inside the ball tries to match the temperature of the water outside, pressure builds up as a result, popping the dented part back into place. This shows how an increase in temperature caused a proportional increase in pressure according to Charles Law.· The Soda CanBeer or soda cans and bottles have a label on them stating, "Store in a cool, dry place". The reason, being that these cans have a lot artificial pressure stored in them, is when exposed to direct sunlight or heat, the pressure inside the cans rise. However, since the volume is constant, the pressure increases to a limit where they burst, letting out all the pressure. The temperature increase in the can resulted in the increase in pressure, resulting in the explosion.· The BalloonImagine a balloon filled with helium on a cold winter day. While you are in the shop, the balloon is normal. As you step outside the balloon begins to shrivel up. This happens because of the temp. of the helium in the balloon deceases and becomes less dense, because the helium particles lose energy and become more concentrated, decreasing the volume. But when you put the balloon in a warm area, it goes back to its original size.· The Bicycle TiresYou go out one day on a winter day and ride your bicycle. After a couple of hours of travelling around the neighbourhood or the city, you noticed the tires are getting flatter even if there is no puncture mark on it. This happened because if the weather gets colder, the air in your bike tires will shrink in volume and they will go flat.· The Hot-Air BalloonsWhen flying-hot air balloons, balloonists apply the principle of Charles' law. As the air inside the balloon is heated, its volume increases. The density of the air decreases as the air inside the balloon is heated; it expands, resulting in an increase in density of the air inside the balloon. The density of hot air is less than of cold air. The difference in density between the air inside and outside the balloon makes the hot-air balloon rise.
Why does air pressure increase at lower altitudes?
The air molecules have mass. When a lot of molecues are piled up,one on top the other, the pressure increases because of that.So air pressure increases at lower altitudes.
If a balloon is squeezed what happens to the pressure of the gas inside the balloon?
If a balloon is squeezed, then that means the volume is decreasing. Volume and pressure vary indirectly, which means that when one goes up, the other goes down. So when you are decreasing the volume of the balloon, the pressure inside is going up (assuming constant mass and temperature).
Why does a balloon expand until the pressure of the gas inside balloon balances the pressure of the gas outside?
In a closed container where air or other gases tend to occupy space, there is the presence of air pressure that does an upward force. This force exerted inside the balloon able the balloon to fly, but there is an opposing force outside it, which is also air pressures. Hence, the air pressure inside the balloon must be greater than the air pressure outside it, for the balloon to be lifted up. I'm not sure this guy ^ answered your question or not. Actually, it's completely wrong. If you ARE talking about helium balloons, as he seemed to be, then Helium is a lighter gas than the combined gases in the air. Just like mixing olive oil and water, denser objects sink, and lighter objects float. Therefore, a helium balloon will float upwards until it pops. If you WEREN'T talking about helium balloons, which I don't think you were, then you're like me. I've been doing some research to prove my theory. While hard to find, it seems to be pretty common knowledge in science (and yet, for some reason, my teacher was wrong about it - hence me doing outside research) that a balloon has a greater air pressure inside the wall than that outside. Air pressure, technically, is a measurement of the amount of collisions against a surface at any time. In the case of balloon, it's supposed to measure how many particles at any in any given time space collide with the wall of the balloon and bounce off. However, since this is near impossible to measure, air pressure seems to be easier described as density. The similarity comes from the idea that when there are more molecules in the same space, more of them will be heading towards a collision course with the wall. The first concept of air pressure within a balloon that you will need to know is that air pressures "try" to even out. With all the bouncing against the balloon wall (both in and out) there will be a certain amount of expansion/contraction. As air pressure itself is a description of the total forces against an object, each of these forces, on the outside of the balloon, causes the balloon to contract a tiny bit, while the inside forces cause the balloon to expand. With this knowledge, one would immediately assume the a balloon with high air pressure inside would expand based on the high amount of internal forces, and vice versa. This would make the inside and outside air pressures equal. However, the part I am looking for, that my science teacher doesn't agree with, is the fact that we are, after all, talking about balloons. Balloons have a certain elasticity to them that some won't take into account. When you stretch a balloon, you're filling it with potential energy. When you let it go, the potential energy is turned into kinetic energy and the balloon snaps back into its original position (though perhaps a little stretched out). When you fill up a balloon with air, the balloon is being stretched. While the balloon is constantly releasing kinetic energy in an attempt to contract, it is also being pushed back out by the constant bouncing of the internal air molecules. Because I'm still researching this, I'm not an expert, but basically, the internal air has to exert force not only to counteract the external air to keep the air pressures "even," but it also has to counteract the natural contraction of the balloon. Therefore, it requires more air pressure (more force) than the air outside the balloon wall. ________________________________________________________________ the gas pressure inside an inflated balloon always greater than the air pressure outside because as the atoms and molecules move about they hit the wall of the balloons which increases their speed so the gas pressure is higher then outside. The air pressure outside the wall is less because atoms and molecules can easily move about. When most of the atoms and molecules escape from the balloon the air becomes same outside and inside. ________________________________________________________________ Okay, no, that ^ just doesn't make any sense. Hitting the balloon wall does not increase speed. Also, the air outside the balloon is generally confined too. It is bouncing off the balloon, all of the objects in it's area, possibly walls and a ceiling... And, according to your theory, if air is let out, what's left would still have a greater pressure, because it's still hitting the walls...not that this 'theory' makes any sense...
