To find the pH from the pOH, you use the formula pH + pOH = 14. Therefore, if the pOH is 4.8, then the pH would be 9.2 (14 - 4.8 = 9.2).
The pOH of ammonia is approximately 4.7. Ammonia, NH3, is a weak base with a Kb value of approximately 1.8 x 10^-5. To find the pOH, you would first find the pH of the solution using the equilibrium constant for the base dissociation reaction and then use the relationship pOH = 14 - pH.
The pOH is 6,4.
10.7(pH) - 14 = 3.3 (pOH)
1.8
pOH = 14 - pH 5 = 14 - pH 9 = pH
Calculations of "pOH" are performed regularly in the field and profession of chemistry. This is performed by comparing "pOH" to the "pH" of a substance.
pH + pOH =14
The sum is 14 at room temperature.
The pOH is 6,4.
The pOH of ammonia is approximately 4.7. Ammonia, NH3, is a weak base with a Kb value of approximately 1.8 x 10^-5. To find the pOH, you would first find the pH of the solution using the equilibrium constant for the base dissociation reaction and then use the relationship pOH = 14 - pH.
10.7(pH) - 14 = 3.3 (pOH)
1.8
It will have a pOH of 12. Because pH+pOH=14
pH + pOH =14
pH is -log[H(subscript 3)O+] pOH is the [OH-] pOH = 14 - pH apex
pOH = 14 - pH 5 = 14 - pH 9 = pH
pOH +pH=14 pOH+7.6=14 pOH=(14-7.6)=6.4