It will have a pOH of 12. Because pH+pOH=14
It would be an acid since it is less then 7. Also, it is typically a weak acid since is it near a pH of 7 which is a neutral solution.acid
acid=1-6 nuetral=7 base=8-14 the ph scale goes from 1 to 14
on a PH scale 7 is neutral. So any number close to 7 is considered weak be it a base or an acid.
You usually calculate it with a pH stick. Good question!!.
The pH scale goes as follows : |____________|___________| 0 ACIDIC 7 BASIC 14 Below 7 = Acid More than 7 = Base
First u need to know the pH of sulfuric acid: ph= -log[h+] =-log[0.4] 0.3979 now u can find out the POH of sulfuric acid ph+poh=14 poh=14-0.3979 poh=13.6
1.8
pH is -log[H(subscript 3)O+] pOH is the [OH-] pOH = 14 - pH apex
pH + pOH =14
pH 1 to 2.Sulfuric acid is a strong diprotic acid: [H+] = 2* 0.15 = 0.30 mole/L H+pH = -log 0.30 = 0.52pH 2.
The pOH is 6,4.
10.7(pH) - 14 = 3.3 (pOH)
pH + pOH =14
To find the pH from the pOH, you use the formula pH + pOH = 14. Therefore, if the pOH is 4.8, then the pH would be 9.2 (14 - 4.8 = 9.2).
pOH = 14 - pH 5 = 14 - pH 9 = pH
The pH of a 0.0110 M solution of Ba(OH)2 can be calculated by finding the hydroxide ion concentration, which is double the concentration of the Ba(OH)2 solution. Therefore, [OH-] = 2 * 0.0110 M = 0.0220 M. From this, you can calculate the pOH using the formula -log[OH-], and then convert pOH to pH using the relation pH + pOH = 14.
pOH +pH=14 pOH+7.6=14 pOH=(14-7.6)=6.4