First u need to know the pH of sulfuric acid:
ph= -log[h+]
=-log[0.4]
0.3979
now u can find out the POH of sulfuric acid
ph+poh=14
poh=14-0.3979
poh=13.6
"This Is Acid" is a song by Maurice Joshua featuring Hot Hands Hula and was released in 1989.
Molarity = moles of solute/Liters of solutionMoles of solute = Liters of solution * Molarity ( 100 mL = 0.1 Liters )Moles of NaCl = 0.1 Liters * 0.20 M NaCl= 0.02 moles NaCl============
The molar ratio of O2 to SO2 in the reaction 2SO2 + O2 -> 2SO3 is 1:1. This means that one mole of O2 reacts with two moles of SO2 to produce two moles of SO3.
To calculate the number of moles of NaI in 50.0mL of a 0.400M solution, you first need to convert the volume to liters by dividing by 1000 (since 1L = 1000mL). Then, use the formula moles = Molarity x Volume (in liters) to find the number of moles of NaI. In this case, it would be 0.400 mol/L x 0.050 L = 0.020 moles of NaI.
The balanced chemical equation for the reaction between oxygen and hydrogen is2H2 + 02 -> 2H2OThus 2.2 moles of oxygen reacts with 4.4 moles of hydrogen to form 4.4 moles of steam (water in gaseous state).The mass of H2O obtained is thus 4.4 x 18.0 = 79.2g.
15 moles of 02 equal 480 g.
The answer is 1,72 moles.
"This Is Acid" is a song by Maurice Joshua featuring Hot Hands Hula and was released in 1989.
Molarity = moles of solute/Liters of solutionMoles of solute = Liters of solution * Molarity ( 100 mL = 0.1 Liters )Moles of NaCl = 0.1 Liters * 0.20 M NaCl= 0.02 moles NaCl============
The molar ratio of O2 to SO2 in the reaction 2SO2 + O2 -> 2SO3 is 1:1. This means that one mole of O2 reacts with two moles of SO2 to produce two moles of SO3.
The balanced equation is C3H8 + 5O2 ---> 3CO2 + 4H2O moles C3H8 = 23.7 g x 1 mol/44 g = 0.539 moles moles O2 needed = 5 x 0.539 moles = 2.695 moles O2 (it takes 5 moles O2 per mole C3H8) grams O2 needed = 2.695 moles x 32 g/mole = 86.2 grams O2 needed (3 sig figs)
To calculate the number of moles in a solution, use the formula: moles = molarity x volume (in liters). First, convert 10.0 mL to liters by dividing by 1000 (10.0 mL = 0.01 L). Then, multiply the molarity (2.0 M) by the volume in liters to find the number of moles. Therefore, in 10.0 mL of a 2.0 M solution, there are 0.02 moles of potassium carbonate.
You have to burn C3H8 in O2. You get 3CO2 plus 4H2O. So to burn one mole of C3H8, you need 5 moles of O2. That means you need one fifth of C3H8 as compared to O2. So you need 0.567/5 = 0.1134 moles of C3H8. Hence the answer.
To calculate the number of moles of NaI in 50.0mL of a 0.400M solution, you first need to convert the volume to liters by dividing by 1000 (since 1L = 1000mL). Then, use the formula moles = Molarity x Volume (in liters) to find the number of moles of NaI. In this case, it would be 0.400 mol/L x 0.050 L = 0.020 moles of NaI.
dilute 1.7 ml of Conc. HCl to 1000 ml with water
The balanced chemical equation for the reaction between oxygen and hydrogen is2H2 + 02 -> 2H2OThus 2.2 moles of oxygen reacts with 4.4 moles of hydrogen to form 4.4 moles of steam (water in gaseous state).The mass of H2O obtained is thus 4.4 x 18.0 = 79.2g.
The reaction between benzoic acid and ammonia to form benzamide is represented by the following equation: C6H5COOH + NH3 -> C6H5CONH2 + H2O