The answer is 1,72 moles.
15 moles of 02 equal 480 g.
At STP (Standard Temperature and Pressure), 1 mole of any ideal gas occupies 22.4 liters. Since 11.2 liters represent half the volume of a mole, we have 0.5 moles of O2 gas. Using the molar mass of oxygen (O2), which is around 32 g/mol, we find that 0.5 moles of O2 gas would be equivalent to approximately 16 grams.
Well, isn't that a happy little question! At standard temperature and pressure (STP), one mole of any gas occupies about 22.4 liters of space. So, for 0.05 moles of neon gas at STP, the volume would be 0.05 moles multiplied by 22.4 liters/mole, giving us 1.12 liters. Just imagine all that neon gas peacefully floating around in that volume, creating a lovely little atmosphere!
The balanced equation is C3H8 + 5O2 ---> 3CO2 + 4H2O moles C3H8 = 23.7 g x 1 mol/44 g = 0.539 moles moles O2 needed = 5 x 0.539 moles = 2.695 moles O2 (it takes 5 moles O2 per mole C3H8) grams O2 needed = 2.695 moles x 32 g/mole = 86.2 grams O2 needed (3 sig figs)
There is no such thing as 02 gas. Perhaps you meant O2 gas, which is oxygen gas, consisting of molecules made of two oxygen atoms bonded together. O2 is essential for respiration in living organisms and combustion in fires.
15 moles of 02 equal 480 g.
The balanced chemical equation for the reaction between oxygen and hydrogen is2H2 + 02 -> 2H2OThus 2.2 moles of oxygen reacts with 4.4 moles of hydrogen to form 4.4 moles of steam (water in gaseous state).The mass of H2O obtained is thus 4.4 x 18.0 = 79.2g.
At STP (Standard Temperature and Pressure), 1 mole of any ideal gas occupies 22.4 liters. Since 11.2 liters represent half the volume of a mole, we have 0.5 moles of O2 gas. Using the molar mass of oxygen (O2), which is around 32 g/mol, we find that 0.5 moles of O2 gas would be equivalent to approximately 16 grams.
Since we know that one mole of any gas at STP is equal to 22.4 L we can multiply 135L by the following conversion: 1 mole/22.4L. When you set up the problem it looks like this: (135L)x 1 mole/22.4L =6.03 moles of oxygen gas The liters cancel out and you are left with moles as your units. Remember, if you have liters and want moles, divide by 22.4 liters; if you have moles and you want liters you multiply by 22.4 liters.
Well, isn't that a happy little question! At standard temperature and pressure (STP), one mole of any gas occupies about 22.4 liters of space. So, for 0.05 moles of neon gas at STP, the volume would be 0.05 moles multiplied by 22.4 liters/mole, giving us 1.12 liters. Just imagine all that neon gas peacefully floating around in that volume, creating a lovely little atmosphere!
Gas engine has two, diesel has zero.
You have to burn C3H8 in O2. You get 3CO2 plus 4H2O. So to burn one mole of C3H8, you need 5 moles of O2. That means you need one fifth of C3H8 as compared to O2. So you need 0.567/5 = 0.1134 moles of C3H8. Hence the answer.
Molarity = moles of solute/Liters of solutionMoles of solute = Liters of solution * Molarity ( 100 mL = 0.1 Liters )Moles of NaCl = 0.1 Liters * 0.20 M NaCl= 0.02 moles NaCl============
no, but Ozone is
The balanced equation is C3H8 + 5O2 ---> 3CO2 + 4H2O moles C3H8 = 23.7 g x 1 mol/44 g = 0.539 moles moles O2 needed = 5 x 0.539 moles = 2.695 moles O2 (it takes 5 moles O2 per mole C3H8) grams O2 needed = 2.695 moles x 32 g/mole = 86.2 grams O2 needed (3 sig figs)
To calculate the number of moles in a solution, use the formula: moles = molarity x volume (in liters). First, convert 10.0 mL to liters by dividing by 1000 (10.0 mL = 0.01 L). Then, multiply the molarity (2.0 M) by the volume in liters to find the number of moles. Therefore, in 10.0 mL of a 2.0 M solution, there are 0.02 moles of potassium carbonate.
1 mole of 02 gas has 12,044 281 714.1023 atoms.