The perimeter is 8*505 = 44 cm.
A rectangle has two pairs of equal sides. So to calculate the perimeter, add two known sides and multiply by two. 45 + 10 = 55 55 x 2 = 110 Perimeter - 110 metres.
Since a square has four sides of equal length: 220 / 4 = 55 units per side.
The area doesn't tell you the dimensions or the perimeter. It doesn't even tell you the shape. The shortest perimeter that could enclose that area would be a circle. The shortest perimeter with straight sides would be a square. If it's a rectangle, then there are an infinite number of them, all with different dimensions and different perimeters, that all have the same area.
23 ______ | | 23 | | 23 |_____| 23 Add up the sides: 23 + 23 + 23 + 23 = 92 92 cm squared
A 55-sided regular polygon would be called a pentacontakaipentagon.
6 * 55 mm = 330 mm
A rectangle has two pairs of equal sides. So to calculate the perimeter, add two known sides and multiply by two. 45 + 10 = 55 55 x 2 = 110 Perimeter - 110 metres.
Since a square has four sides of equal length: 55 feet x 4 sides = 220 feet perimeter.
It will have 55 sides
All of the central angles in any polygon add up to 360 degrees.If the octogon is regular ... all of its central angles are equal ...then each of them is 45 degrees.
13 cm and it is an isosceles triangle 55 - 2*21 = 13
Since a square has four sides of equal length: 220 / 4 = 55 units per side.
A pentagon, which is a 5-sided figure, might have sides that are 11 inches long. But there are an infinite number of other lengths possible. If we are talking about a regular pentagon with a perimeter of 55 inches, then yes, each side of that pentagon is 11 inches long.
1 pentagon = 5 sides. 55 pentagons = 5*55 = 275 sides.
The area doesn't tell you the dimensions or the perimeter. It doesn't even tell you the shape. The shortest perimeter that could enclose that area would be a circle. The shortest perimeter with straight sides would be a square. If it's a rectangle, then there are an infinite number of them, all with different dimensions and different perimeters, that all have the same area.
23 ______ | | 23 | | 23 |_____| 23 Add up the sides: 23 + 23 + 23 + 23 = 92 92 cm squared
If the perimeter is 220 cucumbers, the length of one side is 220 cucumbers ÷ 4 or 55 cucumbers. So the area is 55 cucumbers x 55 cucumbers or 3025 square cucumbers.