An array of pointers is exactly what it sounds like - one or more pointers arranged in order in memory, accessible through a common base name and indexed as needed. Philosophically, there is no difference between an array of pointers and an array of objects...
int a[10]; // 10 integers, named a[0], a[1], a[2], ..., a[9]
int *b[10]; // 10 pointers to int, named b[0], b[1], b[2], ..., b[9]
If you initialize the array of pointers...
int i;
for (i = 0; i < 10; i++) b[i] = &a[i];
... then *b[0] would be the same as a[0], etc.
an array of pointer
Arrays are implemented as pointers in c.
Yes, passing an array name to a pointer assigns the first memory location of the array to the pointer variable. An array name is the same as a pointer to the first location of the array, with the exception that an array name is a r-value, while a pointer is an l-value.
When an array name is passed as a function argument, the address of the first element is passed to the function. In a way, this is implicit call by reference. The receiving function can treat that address as a pointer, or as an array name, and it can manipulate the actual calling argument if desired.
constant pointer and character pointer
By returning a pointer to the first element of the array.
In the C and C++ languages the array notation arr[i] is completely equivalent to the pointer notation *(arr + i).
Yes, passing an array name to a pointer assigns the first memory location of the array to the pointer variable. An array name is the same as a pointer to the first location of the array, with the exception that an array name is a r-value, while a pointer is an l-value.
A pointer into an array of elements of type E is a pointer to a single element of type E:typedef ..... E;E array[123];E* const pointer = &array[18]; // points to the 19th element inside 'array'An array of pointers is an array whose elements are pointers:typedef .... E;E* array[123];E** const pointer = &array[18]; // points to the 19th pointer within 'array'Referencing the name of the array variable without use of the index operator itself is a constant pointer to its first element. Therefore, the following if-clause is always true:typedef .... E;E array[123];if (array &array[N]) { // ALWAYS true ...}
When an array name is passed as a function argument, the address of the first element is passed to the function. In a way, this is implicit call by reference. The receiving function can treat that address as a pointer, or as an array name, and it can manipulate the actual calling argument if desired.
because u freakin can
constant pointer and character pointer
once we initialize the array variable, the pointer points base address only & it's fixed and constant pointer
By returning a pointer to the first element of the array.
In the C and C++ languages the array notation arr[i] is completely equivalent to the pointer notation *(arr + i).
A pointer is a variable that holds address information. For example, in C++, say you have a Car class and another class that can access Car. Then, declaring Car *car1 =new Car() creates a pointer to a Car object.. The variable "car1" holds an address location.
the simple and efficient way to pass an array is pointer to an array like that int (*p)[30] ; // pointer to an array of integer having 30 element
You cannot add elements to a fixed array in C or C++. If, however, the array is declared as a pointer to an array, you can add elements by allocating a new array, copying/adding elements as needed, reassigning the new array to the pointer, and deallocating the original array.
An array behaves like a pointer when you use its name in an expression without the brackets.int a[10]; /* a array of 10 ints */int *b = a; /* a reference to a as a pointer, making b like a */int c = *(a+3); /* a reference to a[3] using pointer semantics */myfunc(a); /* pass a's address, a pointer to myfunc */Note very carefully that, while an array name and a pointer can almost always be interchanged in context, the are not the same, in that a pointer is an l-value, such as b, above, and can be assigned, whereas a is an r-value and can only be referenced, such as in the same statement, the second statement. Also, an array name does not take up memory, while a pointer does.