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The balanced reaction of LiOH + CO2 to produce Li2CO3 + H2O is as follows. 2 LiOH + CO2 --> Li2CO3 + H2O.
NH4OH(aq) + HNO3(aq) --> NH4NO3(aq) + H2O(l) Aqueous ammonium nitrate and water are products.
SeO2 (s) + 2KOH(aq) > K2SeO3(aq) +H2O(l) SeO2(s)+2KOH(aq)→K2SeO3(aq)+H2O(l)
CaCO3(s) + 2HCl(aq) -> CaCl2(aq) + H2CO3(aq) is the balanced chemical equation H2CO3 is not stable in this form, so it splits into CO2(g) + H2O(l) Therefore the true equation will be: CaCO2(s) + 2HCl(aq) -> CaCl2(aq) + CO2(g) + H2O(l) You NIE will start like this: CaCO2(s) + 2H+(aq) + 2Cl-(aq) -> Ca2+(aq) + 2Cl-(aq) + CO2(g) + H2O(l) and will end as: 2H+(aq) + CaCO2(s) -> Ca2+(aq) + CO2(g) + H2O(l)
AlCl3 & H2O AlCl3 & H2O Solving Al2O3 (s) in HCl Al2O3 (s) + 6 HCl (aq) → 2 [AlCl3] (s, aq*) + 3 H2O (l) *depending on amount of acid used. Excessive amounts of acid will solve the formed AlCl3 (s) into 2([Al3+][Cl-]3) (aq)
Li2O + H2O -> 2 LiOHCorrect answer: Li2O(s)+H2O(l) -> 2LiOH(aq)
Lithium oxide, and water are the reactants. Lithium hydroxide is the product. Here is the balanced reaction equation. Li2O(s) + H2O(l) = 2LiOH(aq)
LiOH(aq)
lithium + water lithium hydroxide + hydrogen. 2Li(s) + 2H2O(l) 2LiOH(aq) + H2(g)
Na2CrO4 (aq) + 2LiOH (aq) -----> Li2CrO4 (s) + 2NaOH (aq)
H2O(l) is in the liquid state. That is what the (l) means.
The balanced reaction of LiOH + CO2 to produce Li2CO3 + H2O is as follows. 2 LiOH + CO2 --> Li2CO3 + H2O.
KHC8H4O4(aq) + NaOH(aq) → KNaC8H4O4(aq) + H2O(l) NaOH(aq) + KHP(aq) => Na+ + KP- + H2O(l)
HNO3 (aq) + NaOH (aq) --> H2O (l) + NaNO3 (aq)
This is an acid base reaction, a salt and water is produced. The equation looks like this:HCl(aq) + NaOH(aq) => H2O(l) + NaCl(aq)
Will sodium carbonate react with hydrochloric acid. 2HCI(aq) NA2CO3(aq)--- 2NaCI(aq) H2O(aq) CO2(aq)?
2 Li(s) + 2H2O(l) = 2LiOH(aq) +H2(g) the lithium hydroxide is aqueous because it is in solution.