K. C. Pant has written: 'India on the move'
india me...bht jyada hai...up me for eng, almost 50 k aas pas..
The answer is 882.85 C (approx.). The Kelvin scale starts at absolute zero and is used in scientific laboratories. Celsius is for general use and set 0 and 100 as melting and boiling point of water respectively. To convert from K to C, subtract 273.15 from K.1156 K = 882.85 deg C
The answer is 153.15 K (approx.). The Kelvin scale starts at absolute zero and is used in scientific laboratories. Celsius is for general use and set 0 and 100 as melting and boiling point of water respectively. To convert from C to K, add 273.15 to C.-120 c = -153.15 k
The answer is 311.05 K (approx.). The Kelvin scale starts at absolute zero and is used in scientific laboratories. Celsius is for general use and set 0 and 100 as melting and boiling point of water respectively. To convert from C to K, add 273.15 to C.37.9 deg C = 311.5 K
c k nayudu
The answer is 1337.15 K (approx.). The Kelvin scale starts at absolute zero and is used in scientific laboratories. Celsius is for general use and set 0 and 100 as melting and boiling point of water respectively. To convert from C to K, add 273.15 to C.1064 deg C = 1337.15 deg K
The answer is 14.15 K (approx.). The Kelvin scale starts at absolute zero and is used in scientific laboratories. Celsius is for general use and set 0 and 100 as melting and boiling point of water respectively. To convert from C to K, add 273.15 to C.Kelvin = Celsius + 273.15-259 C + 273.15 = 14.15 K
The answer is 157.85 C (approx.). The Kelvin scale starts at absolute zero and is used in scientific laboratories. Celsius is for general use and set 0 and 100 as melting and boiling point of water respectively. To convert from K to C, subtract 273.15 from K.158 deg C is closest.
The answer is 363.15 K (approx.). The Kelvin scale starts at absolute zero and is used in scientific laboratories. Celsius is for general use and set 0 and 100 as melting and boiling point of water respectively. To convert from C to K, add 273.15 to C.90 degrees C = (90 + 273.15) = 363.15 K
The answer is 1073.15 K (approx.). The Kelvin scale starts at absolute zero and is used in scientific laboratories. Celsius is for general use and set 0 and 100 as melting and boiling point of water respectively. To convert from C to K, add 273.15 to C.
The answer is 98.15 K (approx.). The Kelvin scale starts at absolute zero and is used in scientific laboratories. Celsius is for general use and set 0 and 100 as melting and boiling point of water respectively. To convert from C to K, add 273.15 to C.-175 deg C = -175 + 273.15 = 98.15 K