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A rhombus has four equal sides but is not square; rather it is a diamond shape, so a rhombic antenna will have rhombus shaped metal parts which receive radio waves.
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What is the adjective form of rhombus?
The adjective for a rhombus or rhomboid is rhombic.
Solid figure with 6 faces?
Cube * * * * * A cube is a very special case. A more general one would be a rectangular prism (shape of a brick). Even more would be a rhombic hexahedron.
What is cut stone?
When a stone comes out of the ground it may have different shapes, cubes, rhombic or dodecahedral. None of those shapes have the brilliance, shape or shine that you'd associate with the rings and necklaces at your local jeweler. So, rough stones are sent to a cutter who uses various tools and polishing methods to shape and smooth the stone to get the best possible aesthetics from it. When the cutter is done it has gone from being a rough to a cut stone.
A shape with 7 silds is called a?
7,5,3 is impossible, because an odd shape, meeting two others, forces the others to be equal. Here is a generalization of that rule. Let each corner have the pattern x,y,z,y where all three variables are different and y is odd. Walk around y back to start and arrive at a contradiction. The same is true of x,y,z,z and x,y,y,x and x,y,y,z. Thus 6,3,3,4 is impossible, even though the angles sum to less than 360°. When building semiregular solids, we don't have to worry about anything beyond the octagon. Here's why. Let x be a 9-gon or higher, hence it consumes 140° or more. Note that x cannot join four other shapes at a vertex, and if it joins three other shapes, two of them must be triangles. If the third is a triangle we have the anti-gonal prism. If the third is a square, x,3,4,3 and x,4,3,3 both fail the walkaround test. If the third is a pentagon the angles exceed 360°. Thus x meets two other shapes. If one is a triangle the other must be x, which is valid for x < 12. Yet if x is odd, and greater than 3, it fails the walk around test. Therefore the semiregular solid x,3,x is valid for x = 3, 4, 6, 8, 10. That takes care of x meeting a triangle. Without a triangle, x meets squares or higher. If x meets two squares we have the gonal prism. The shape x,4,5 fails the walkaround test, and x,4,6 fails the walk around test when x = 9 or 11. The pattern x,4,6 is valid when x = 10, another use for the decagon. These shapes consume too much angle when x is 12 or higher. Finally, x,5,5 fails the walk around test, and x,5,6 is too big. Hereinafter, we can restrict attention to octagons and below. If the octagon meets three other shapes, two of them are triangles. Let the third be a square, to avoid the anti-gonal prism. Yet 8,3,4,3 and 8,3,3,4 fail the walkaround test, so the octagon meets two other shapes. If one of them is odd then the other is an octagon, and that only leaves room for a triangle. This is 8,8,3, the truncated cube. If the octagon meets two even shapes, one of them is a square. To avoid the gonal prism, the other is a hexagon. This is another valid shape. That takes care of the octagon. If a heptagon, 7 sides, meets three shapes, two of them are triangles. The third creates the anti-gonal prism, or fails the walkaround test, hence the heptagon meets two other shapes. Since 7 is odd, these shapes are equal. They must be even, else we fail the walkaround test. Skip the squares (gonal prism) and move to hexagons, but that introduces too much angle. If a pentagon meets two other shapes they too are pentagons, or they are copies of an even shape, a square (gonal prism) or a hexagon (soccer ball). If the pentagon meets four other shapes they are triangles, and that is valid. If the pentagon meets three other shapes, at least one is a triangle. If the second is a triangle, the third should not be a triangle, else we have an anti-gonal prism. Note that 5,3,3,4 5,3,4,3 5,3,3,5 5,3,3,6 5,3,6,3 all fail the walkaround test. That leaves 5,3,5,3, which is valid. If the third shape is a square then so is the fourth. Since 5,3,4,4 fails, we are left with 5,4,3,4, which is valid. That's it for the pentagon. Join two hexagons with a triangle or a square; both are valid. Hereinafter there is at most one hexagon; everything else being squares or triangles. If a hexagon meets two shapes, one cannot be a triangle, so we're talking about two squares, the gonal prism. If the hexagon meets 3 other shapes, the first two are triangles. Make the third a square, avoiding the anti-gonal prism. Yet 6,3,3,4 and 6,3,4,3 both fail the walkaround test. That's it for the hexagon. Three squares and a triangle - that works. Two squares and two triangles makes the shape 4,3,4,3. One square joins 4 triangles to make a snub solid. That's all the semiregular solids. They are presented in the table below. {| ! Name ! Pattern ! Vertices ! Edges ! Faces | Gonal Prism n,4,4 2n 3n n+2 Anti-gonal Prism n,3,3,3 2n 4n 2n+2 Tetrahedron 3,3,3 4 6 4 Cube 4,4,4 8 12 6 Octahedron 3,3,3,3 6 12 8 Dodecahedron 5,5,5 20 30 12 Icosahedron 3,3,3,3,3 12 30 20 Truncated Tetrahedron 6,6,3 12 18 8 Truncated Cube 8,8,3 24 36 14 Truncated Octahedron 6,6,4 24 36 14 Truncated Dodecahedron 10,10,3 60 90 32 Truncated Icosahedron 6,6,5 60 90 32 Cuboctahedron 4,3,4,3 12 24 14 Icosidodecahedron 5,3,5,3 30 60 32 Truncated Cuboctahedron 8,6,4 48 72 26 Truncated Icosidodecahedron 10,6,4 120 180 62 Rhombic Cuboctahedron 4,4,4,3 24 48 26 Rhombic Icosidodecahedron 5,4,3,4 60 120 62 Snub Cuboctahedron 4,3,3,3,3 24 60 38 Snub Icosidodecahedron 5,3,3,3,3 60 150 92 |} 7,5,3 is impossible, because an odd shape, meeting two others, forces the others to be equal. Here is a generalization of that rule. Let each corner have the pattern x,y,z,y where all three variables are different and y is odd. Walk around y back to start and arrive at a contradiction. The same is true of x,y,z,z and x,y,y,x and x,y,y,z. Thus 6,3,3,4 is impossible, even though the angles sum to less than 360°. When building semiregular solids, we don't have to worry about anything beyond the octagon. Here's why. Let x be a 9-gon or higher, hence it consumes 140° or more. Note that x cannot join four other shapes at a vertex, and if it joins three other shapes, two of them must be triangles. If the third is a triangle we have the anti-gonal prism. If the third is a square, x,3,4,3 and x,4,3,3 both fail the walkaround test. If the third is a pentagon the angles exceed 360°. Thus x meets two other shapes. If one is a triangle the other must be x, which is valid for x < 12. Yet if x is odd, and greater than 3, it fails the walk around test. Therefore the semiregular solid x,3,x is valid for x = 3, 4, 6, 8, 10. That takes care of x meeting a triangle. Without a triangle, x meets squares or higher. If x meets two squares we have the gonal prism. The shape x,4,5 fails the walkaround test, and x,4,6 fails the walk around test when x = 9 or 11. The pattern x,4,6 is valid when x = 10, another use for the decagon. These shapes consume too much angle when x is 12 or higher. Finally, x,5,5 fails the walk around test, and x,5,6 is too big. Hereinafter, we can restrict attention to octagons and below. If the octagon meets three other shapes, two of them are triangles. Let the third be a square, to avoid the anti-gonal prism. Yet 8,3,4,3 and 8,3,3,4 fail the walkaround test, so the octagon meets two other shapes. If one of them is odd then the other is an octagon, and that only leaves room for a triangle. This is 8,8,3, the truncated cube. If the octagon meets two even shapes, one of them is a square. To avoid the gonal prism, the other is a hexagon. This is another valid shape. That takes care of the octagon. If a heptagon, 7 sides, meets three shapes, two of them are triangles. The third creates the anti-gonal prism, or fails the walkaround test, hence the heptagon meets two other shapes. Since 7 is odd, these shapes are equal. They must be even, else we fail the walkaround test. Skip the squares (gonal prism) and move to hexagons, but that introduces too much angle. If a pentagon meets two other shapes they too are pentagons, or they are copies of an even shape, a square (gonal prism) or a hexagon (soccer ball). If the pentagon meets four other shapes they are triangles, and that is valid. If the pentagon meets three other shapes, at least one is a triangle. If the second is a triangle, the third should not be a triangle, else we have an anti-gonal prism. Note that 5,3,3,4 5,3,4,3 5,3,3,5 5,3,3,6 5,3,6,3 all fail the walkaround test. That leaves 5,3,5,3, which is valid. If the third shape is a square then so is the fourth. Since 5,3,4,4 fails, we are left with 5,4,3,4, which is valid. That's it for the pentagon. Join two hexagons with a triangle or a square; both are valid. Hereinafter there is at most one hexagon; everything else being squares or triangles. If a hexagon meets two shapes, one cannot be a triangle, so we're talking about two squares, the gonal prism. If the hexagon meets 3 other shapes, the first two are triangles. Make the third a square, avoiding the anti-gonal prism. Yet 6,3,3,4 and 6,3,4,3 both fail the walkaround test. That's it for the hexagon. Three squares and a triangle - that works. Two squares and two triangles makes the shape 4,3,4,3. One square joins 4 triangles to make a snub solid. That's all the semiregular solids. They are presented in the table below. {| ! Name ! Pattern ! Vertices ! Edges ! Faces | Gonal Prism n,4,4 2n 3n n+2 Anti-gonal Prism n,3,3,3 2n 4n 2n+2 Tetrahedron 3,3,3 4 6 4 Cube 4,4,4 8 12 6 Octahedron 3,3,3,3 6 12 8 Dodecahedron 5,5,5 20 30 12 Icosahedron 3,3,3,3,3 12 30 20 Truncated Tetrahedron 6,6,3 12 18 8 Truncated Cube 8,8,3 24 36 14 Truncated Octahedron 6,6,4 24 36 14 Truncated Dodecahedron 10,10,3 60 90 32 Truncated Icosahedron 6,6,5 60 90 32 Cuboctahedron 4,3,4,3 12 24 14 Icosidodecahedron 5,3,5,3 30 60 32 Truncated Cuboctahedron 8,6,4 48 72 26 Truncated Icosidodecahedron 10,6,4 120 180 62 Rhombic Cuboctahedron 4,4,4,3 24 48 26 Rhombic Icosidodecahedron 5,4,3,4 60 120 62 Snub Cuboctahedron 4,3,3,3,3 24 60 38 Snub Icosidodecahedron 5,3,3,3,3 60 150 92 |}
Why honey comb is in hexagonal prism?
honeycomb is a mass of hexagonal wax cells built by honey bees in their nests to contain their larvae and stores of honey and pollen.Beekeepers may remove the entire honeycomb to harvest honey. Honey bees consume about 8.4 pounds of honey to secrete one pound of wax,[1] so it makes economic sense to return the wax to the hive after harvesting the honey, commonly called "pulling honey" or "robbing the bees" by beekeepers. The structure of the comb may be left basically intact when honey is extracted from it by uncapping and spinning in a centrifugal machine-the honey extractor. Fresh, new comb is sometimes sold and used intact as comb honey, especially if the honey is being spread on bread rather than used in cooking or to sweeten tea.Broodcomb becomes dark over time, because of the cocoons embedded in the cells and the tracking of many feet, called travel stain by beekeepers when seen on frames of comb honey. Honeycomb in the "supers" that are not allowed to be used for brood (e.g. by the placement of a queen excluder) stays light coloured.Numerous wasps, especially polistinae and vespinae, construct hexagonal prism packed combs made of paper instead of wax; and in some species (like Brachygastra mellifica), honey is stored in the nest, thus technically forming a paper honeycomb. However, the term "honeycomb" is not often used for such structures.Honeycomb geometryThe bees begin to build the comb from the top of each section. When filled with honey, the bees seal the cells with wax. Close up of an abandoned Apis florea nest, Thailand. The hexagonal grid of wax cells on either side of the nest are slightly offset from each other. This increases the strength of the comb and reduces the amount of wax required to produce a robust structure.The axes of honeycomb cells are always quasi-horizontal, and the non-angled rows of honeycomb cells are always horizontally (not vertically) aligned. Thus, each cell has two vertical walls, with "floors" and "ceilings" composed of two angled walls. The cells slope slightly upwards, between 9 and 14 degrees, towards the open ends.There are two possible explanations for the reason that honeycomb is composed of hexagons, rather than any other shape. One, given by Jan Brożek, is that the hexagon tiles the plane with minimal surface area. Thus a hexagonal structure uses the least material to create a lattice of cells within a given volume. Another, given by D'Arcy Wentworth Thompson, is that the shape simply results from the process of individual bees putting cells together: somewhat analogous to the boundary shapes created in a field of soap bubbles. In support of this he notes that queen cells, which are constructed singly, are irregular and lumpy with no apparent attempt at efficiency.[2]The closed ends of the honeycomb cells are also an example of geometric efficiency, albeit three-dimensional and little-noticed. The ends are trihedral (i.e., composed of three planes) sections of rhombic dodecahedra, with the dihedral angles of all adjacent surfaces measuring 120°, the angle that minimizes surface area for a given volume. (The angle formed by the edges at the pyramidal apex is approximately 109° 28' 16" (= 180° - arccos(1/3)).)The three-dimensional geometry of a honeycomb cell.The shape of the cells is such that two opposing honeycomb layers nest into each other, with each facet of the closed ends being shared by opposing cells.Opposing layers of honeycomb cells fit together.Honeycomb of the Giant honey bee Apis dorsata in a colony aggregation in Srirangapatnna near BangaloreIndividual cells do not, of course, show this geometric perfection: in a regular comb, there are deviations of a few percent from the "perfect" hexagonal shape. In transition zones between the larger cells of drone comb and the smaller cells of worker comb, or when the bees encounter obstacles, the shapes are often distorted.In 1965, László Fejes Tóth discovered that the trihedral pyramidal shape (which is composed of three rhombi) used by the honeybee is not the theoretically optimal three-dimensional geometry. A cell end composed of two hexagons and two smaller rhombuses would actually be .035% (or approximately 1 part per 2850) more efficient. This difference is too minute to measure on an actual honeycomb, and irrelevant to the hive economy in terms of efficient use of wax, considering that wild comb varies considerably from any mathematical notion of "ideal" geometry
What is anntena?
Any conduction material is called anntena.
What prism has a cross section which is the shape of a rhombus?
A rhombic prism or rhombohedron.A rhombic prism or rhombohedron.A rhombic prism or rhombohedron.A rhombic prism or rhombohedron.
What is the adjective form of rhombus?
The adjective for a rhombus or rhomboid is rhombic.
Is it rhombic antenna a resonant?
No it is not.
When armored cable is used what protection is used at the end?
Mac anntena
What is the density of rhombic sulfur?
0.24
What is a Rhombic star puzzle?
A Rhombic Star Puzzle has 6 indectical peices that when fitted together, make the shape of a ornimental star.
How many vertices does a rhombic prism have?
A rhombus has 4 vertices, therefore a rhombic prism has 4 x 2 = 8 vertices.
How many sides does a Rhombic dodecahedron have?
A rhombic dodecahedron is a 3-D shape (polyhedron) that has 12 rhombic faces, 24 edges (sides), and 14 vertices (points). Its dual is a cuboctahedron. If you wanted to try by yourself, get a transparent model and start counting!
What is the molecular formula of rhombic sulfur?
S8
Examples of non resonant antenna?
Rhombic Antenna....
How much faces does a Rhombic prism have?
6 faces.
