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The formula for the volume of a cube is V=s^3. Take the first derivative----> d/dt(V)= d/dt(s^3) ---->dv/dt= 3s^2 (ds/dt) dv/dt is the propagated error for volume, so the other variables should already be defined in the question where: s= side length and ds/dt would equal possible error in each side. Sometimes it's necessary to solve for these variables using other formulas the most common of which is surface area which is: SA=6s^2 where SA`= dsa/dt= 12s (ds/dt).
If s is the displacement vector of an object at time t, thenvelocity = ds/dt, the derivative of s with respect to tand speed = |ds/dt|, the absolute value of the velocity.
ds/dt=3cm/min, s=10, dA/dt=?First you want a unifying formula, in this case it'd be the Area formula for a square.A=s^2Take the derivative with respect to time.dA/dt=2s*ds/dtSubstitute in known values.dA/dt=2(1)(3)dA/dt=6 cm^2
i need the answer for my dt homework the word begins with a S------------?
d[DeltaDirac(t)]/dt
Rockets work on the conservation of vector energy, cP. 0 = dcP/dr = cdP/cdt=dP/dt = d(mV)/dt = mdV/dt + Vdm/dt=0 Thus, mdV/dt = -Vdm/dt, or (dV/dt)/V = -(dm/dt)/m. The Rocket's mass accelerates at the rate of the mass changes dm/dt.
d/dt cot (t) dt = - cosec2(t)
a = dv/dt =d(vet)/dt =dv/dt *et+det/dt *vwith det =...
A = pi * r2 Take implicit derivative with regard to time for 'rate' type questions: dA/dt = 2 * pi * r * dr/dt dA/dt = 2 * pi * (3 mm) * (10 mm/s) = 60 pi mm2/s
Yes, dD/dt = d0/dt = 0 thusDisplacement D=0 and Velocity dD/dt=d0/dt = o.