speed of efflux = v = √2gh
if height is doubled h=2h
v=√2g(2h)
=√4gh
=√4√gh
=2√gh
v=2√gh
The volume will be doubled.
The area is multiplied by 4, not doubled.
quadrupled. :)
well...if it's doubled then its doubled (just treat it the same)
The area is doubled. a,b - cathetus; c - hypotenuse; h - height; S - area. S = (a*b)/2 = (c*h)/2 obviously if k is the doubled height. and A is the new area. A = (c*k)/2 = (c*2h)/2 = c*h and A = S*2
The volume will be doubled.
Mass will be doubled if the speed is 31/2/2 times the speed of light.
The area is multiplied by 4, not doubled.
As area_of_parallelogram = base x height if they are both doubled then: new_area = (2 x base) x (2 x height) = 4 x (base x height) = 4 x area_of_parallelogram Thus, if the base and height of a parallelogram are [both] doubled, the area is quadrupled.
The tree took 19 years to reach half its maximum height. Since it doubled in height each year, it was half of its maximum height in the year prior to reaching its full height.
If the base stays the same, the area is also doubled.
The area gets doubled.
In the first case, the area will remain the same. In the second case, the area will doubled.
If the mass is doubled,speed should be halved to conserve momentum.
The volume of the cylinder would be doubled.
The volume is doubled.
quadrupled. :)