no, it was invented in chicago, IL
Scott Patton - Guitar, Thad Beaty - Guitar, Brandon Bush - Keyboards and B3 (he is also the brother of mandolin player Kristian Bush), Annie Clements - bass, Travis McNabb - drums Scott Patton - Guitar, Thad Beaty - Guitar, Brandon Bush - Keyboards and B3 (he is also the brother of mandolin player Kristian Bush), Annie Clements - bass, Travis McNabb - drums Their websites can be viewed respectively: scottpattonmusic.com, sortednoise.com, brandonbush.com, annieclementsmusic.com and travismcnabb.com
Ummm . . . it is true that blues music characterisically uses, the minor pentatonic scale. altered. The common blues scale is derived from the usual scale (1,2,3,4,5,6,7,1) by removing the 2nd and 6th notes. That leaves you with the notes, "1,3,4,5,7,1" . There's more to it, though: you flat by a half step the 3rd and the 7th. That results in the notes, 1, b3 (flatted 3rd), 4, 5, b7 - 5 notes in all.
B2 DA bomb obviously!
You have 4 6V batteries. Let's name them B1, B2, B3, B4. Now, let's name the terminals on them, so B1 has B1- and B1+ Now let's name your final output of 24V O- and O+ Connect it like this: B1- to O- B1+ to B2- B2+ to B3- B3+ to B4- B4+ to O+
We know the formula G3=B3 G2=B2 XOR B3 G1=B1 XOR B2 G0=B0 XOR B1
B= Blue R=Red 1= 1st 2=2nd 3=3rd 4=4th First B1,R1,R2,B1,B2,B3,R1,R2,R3,R4,B1,B2,B3,B4,R1,R2,R3,R4,B2,B3,B4,R3,R4,B4.
6 cells. They are A1, A2, A3, B1, B2 and B3.
B1, thiaminB2, riboflavinB3, niacinB6, pyridoxineB12, cobalamin
vitamin b1 is good for the brain
A, b1, b2, b3, b5, b6, b9, c
A1-B3-A3-B2-A2-B1
Suppose you have two sets of n-numbers: {a1, a2, a3, ... , an} and {b1, b2, b3, ... , bn} Then the form for the standard sum of product is a1*b1 + a2+b2 + a3*b3 + ... + an*bn
For two vectors (A & B) in 3-space, using the (i j k) unit vector notation:if A = a1*i + a2*j + a3*k, and B = b1*i + b2*j + b3*k the cross product A X B can be found by computing a determinant of the following matrix:| i j k ||a1 a2 a3 ||b1 b2 b3 |Mathematically, it will look like this: (a2*b3 - a3*b2)*i- (a1*b3 - a3*b1)*j + (a1*b2 - a2*b1)*kI did do just a little copy/paste from the crossproduct website, which I've posted a link to, which has some good information.
You sum up the frequencies upto and including the current band. So if you have data bands b1, b2, b3 and so on with frequencies f1, f2, f3 etc then the cumulative frequency for b1 = f1 b2 = f1+f2 b3 = f1+f2+f3 and so on.