S = v*t s = displacement v = velocity t = time
If you simplify the equation (s+t+s) the answer is 2s+t
s=(v+u)/2*t
The change in entropy between products and reactants in a reaction.
The change in entropy between products and reactants in a reaction.
The change in entropy between products and reactants in a reaction.
Without an equality sign the given expression can't be considered to be an equation. But if you mean: gh = ts then s = gh/t
acceleration = (change in speed) / (time)ora = s/t
The change in entropy between products and reactants in a reaction.
The first half of the question yield two equations:1.I. p = r + (s - r) / 2II. t = r + (p - r) / 2The equation we are solving for, (s - t) / (t - r), does not have a p so we are going to Equation I for the pin Equation II. But first, to make things easier for us, let distribute the 2 in Equation II.2. 2t = 2r + p - r3. 2t = r + pSubstitute I4. 2t = r + r + (s - r) / 25. 2t = 2r + (s - r) / 2Again, lets distribute the 2, and combine the r's6. 4t = 4r + s - r7. 4t = 3r + sIn order to yield the desired quotient, we want a (s - t)on one side of the equation and (t - r) on the other. First let's get the (t - r) on the left.8. 4t - 3r = s9. t + 3t - 3r = s10. t + 3(t - r) = sNow move that extra t over to the right for the (s - t) we are looking for11. 3(t - r) = s - tNow divide both sides by (t - r) and we have our answer!12. 3 = (s - t) / (t - r)
Well the equation is: 6CO2 + 6H2O + -s-u-n-l-i-g-h-t--> C6H12O6 + 6O2.
The d stands for distance.