Are the last two digits of the year divisible exactly by 4?
If the last two digits are"00" are the first two digits divisible exactly by 4?
I believe that in Russia "00" Leap Years are those which leave a remainder of 2 or 6 when the first two digits are divided by 9. This is actually more accurate than the system with which most of the rest of the world is familiar and was originated by the Greek Orthodox Church.
If the year divides evenly by 4 it's a leap year. If it's a century year it has to divide evenly by 400. 2000 was a leap year. 2100 will not be a leap year.
No it is not. A simple algorithm to check this is if the year is divisible by 4, but not by 100, then it is a leap year. Also if a year is divisible evenly by 400, then it is a leap year, but not all leap years are divisible by 400.
leap yr = ((y%100!=0 && yr %400==0)?1:(yr%4==0)?1:0; leap yr =1; printf ("leap yr"); else printf ("not leap yr");
draw a flow chart to find whether the given year is leap year or not
A century is made of 100 years. That is longer than one year, whether it is a normal year or a leap year.
It depends on when you start - whether in a leap year or not, whether your time span includes a xy00 year or not. So there is no simple answer.
There will be a leap year every 4 years except if it is divisible by 100. However, if it is also divisible by 400, it will be a leap year. 2000 was a leap year because it is divisible by 400, but 2100 will not be a leap year.
Because 1500 is a century , so we should check whether it is divisible by 400 not by 4 alone. Since it is not divisible by 400 its not a leap year.1500 WAS actually a leap year, the Gregorian calendar didn't commence until the year 1600.
If you want to determine whether a year is a leap year. Use the cal command for the month of February. So to check 2012, for example, do: cal 2 2012 and see if it prints 28 or 29 days.
Winter solstice happens ever year in the latter part of December. Whether it is a leap year or not has nothing whatsoever to do with it.
#include using namespace std;int main(){short numberOfDays = 0;cout > numberOfDays;if (numberOfDays == 365){cout
are social security going out late because of leap year