We need to know the Molarity (or Molality or formality) of both the acid and the NaOH solution in order to answer this question.
97.8 - 98.2 98 worked for me
40 grams, this is the 1M NaOH standard laboratory solution.
by dissolving the amount you want in mole or grams in one dm3 of water
0.9051 moles Mg per liter of solution. Molarity is the amount of moles per liter of solution. So just divide the number of grams of Mg by its molar mass then divide that by the number of liters
benzoic acid
98g
262 - 266
4.5 grams
262 - 266
Increasing the amount of the solute in the solution the molarity and the density of this solution increases.
97.8 - 98.2 98 worked for me
40 grams, this is the 1M NaOH standard laboratory solution.
To find this answer, you can use a rearranged empirical formula but you need to know how strong the hydrochloric acid is as this will greatly change the amount needed
by dissolving the amount you want in mole or grams in one dm3 of water
0.9051 moles Mg per liter of solution. Molarity is the amount of moles per liter of solution. So just divide the number of grams of Mg by its molar mass then divide that by the number of liters
benzoic acid
When using a solubility curve to make a prediction about the amount of a solute within a solution, you must increase the amount of solute to make a solution, which will give you a concentrated solution