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What amount of NaOH is required to prepare 1N NaOH solution and why only that amount is used?
To prepare a 1N NaOH solution, you would need to dissolve 40 grams of NaOH in water to make 1 liter of solution. This amount is used because 1N solution means 1 mole of NaOH per liter of solution, and the molar mass of NaOH is 40 g/mol, so 40 grams of NaOH is needed to have 1 mole in 1 liter of solution.
What is the amount of solute that dissolves in a given amount of a solution?
The amount of solute that dissolves in a given amount of solution is known as solubility. This can be influenced by factors such as temperature, pressure, and the type of solvent and solute involved. It is typically expressed as grams of solute per 100 grams of solvent.
How much sodium chloride in grams is needed to make 13 L of a solution that has a concentration of 4 grams of sodium chloride per liter of solution?
To calculate the total amount of sodium chloride needed for a 13 L solution at 4 grams per liter, multiply the concentration by the volume of the solution: 4 grams/L x 13 L = 52 grams of sodium chloride. Therefore, you will need 52 grams of sodium chloride to make the 13 L solution.
How can one determine the number of moles present in a solution?
To determine the number of moles in a solution, you can use the formula: moles mass of solute (in grams) / molar mass of solute (in grams per mole). This calculation helps you find the amount of substance in the solution.
If you have a 70 percent solution of dextrose How many grams of dextrose is in 400ml of this solution?
In a 70% dextrose solution, 70% of the total weight is dextrose. To calculate the grams of dextrose in 400ml of this solution, you would multiply 400ml by 70% (or 0.70) to find the amount of dextrose present.
A nitric acid solution is neutralized using sodium hydroxide how many grams of sodium hydroxide are needed to neutralize 3.50L of 0.700 M nitric acid solution?
98g
What mass of sodium benzoate should be added to 160.0 mL of a 0.15 mL benzoic acid solution in order get a buffer with a pH of 4.30?
To create a buffer with a pH of 4.30, you need to use the Henderson-Hasselbalch equation and the pKa of benzoic acid to calculate the ratio of benzoate ion to benzoic acid. From there, you can determine the moles of sodium benzoate needed and then convert it to grams. Make sure to consider the volume change when adding the sodium benzoate to the solution.
A nitric acid solution is neutralized using sodium hydroxide how many grams of sodium hydroxide are needed to neutralize 5.50 L of 1.200M nitric acid solution?
262 - 266
A nitric acid solution is neutralized using sodium hydroxide How many grams of sodium hydroxide are needed to neutralize 5.50 L of 1.200 M nitric acid solution?
262 - 266
How does the amount of solute moles and grams relate to the density and molarity of the solution?
Increasing the amount of the solute in the solution the molarity and the density of this solution increases.
If you have 6.50 molar of chromium which is a molar mass of 52 grams what is the amount in grams of this amount of chromium?
To calculate the amount in grams of chromium in a 6.50 M solution, you would multiply the molarity (6.50 mol/L) by the molar mass of chromium (52 g/mol). This gives you 338g of chromium in 6.50 L of the solution.
What amount of NaOH is required to prepare 1N NaOH solution and why only that amount is used?
To prepare a 1N NaOH solution, you would need to dissolve 40 grams of NaOH in water to make 1 liter of solution. This amount is used because 1N solution means 1 mole of NaOH per liter of solution, and the molar mass of NaOH is 40 g/mol, so 40 grams of NaOH is needed to have 1 mole in 1 liter of solution.
What is the amount of solute that dissolves in a given amount of a solution?
The amount of solute that dissolves in a given amount of solution is known as solubility. This can be influenced by factors such as temperature, pressure, and the type of solvent and solute involved. It is typically expressed as grams of solute per 100 grams of solvent.
How much hydrochloric acid in grams can be neutralized by 3.20 of sodium bicarbonate?
To find this answer, you can use a rearranged empirical formula but you need to know how strong the hydrochloric acid is as this will greatly change the amount needed
How much solute is in a solution?
The concentration of a solution is some measurement of how much solute there is in the solution.
How much sodium chloride in grams is needed to make 13 L of a solution that has a concentration of 4 grams of sodium chloride per liter of solution?
To calculate the total amount of sodium chloride needed for a 13 L solution at 4 grams per liter, multiply the concentration by the volume of the solution: 4 grams/L x 13 L = 52 grams of sodium chloride. Therefore, you will need 52 grams of sodium chloride to make the 13 L solution.
How can one determine the number of moles present in a solution?
To determine the number of moles in a solution, you can use the formula: moles mass of solute (in grams) / molar mass of solute (in grams per mole). This calculation helps you find the amount of substance in the solution.
