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Looks to me like 30,000 BTU or 2 Tons of cooling

@400 CFM per Ton

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11y ago
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Q: What is the Armstrong air conditioner model number SCU10E30A-2 tonnage?
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What is the Armstrong air conditioner model number SCU10E18A-4 tonnage?

It is a 1-1/2 ton: 18000 BTU (unit size)/12,000 BTU (per ton)=1.5


What is amstrong number?

153 is a Armstrong number 13+53+33=153


Write a java program to check a number is Armstrong number?

import java.io.*; public class Jerry { public static void main(String as[]) throws IOException { int k=Integer.parseInt(as[0]); int n=k; int d=0,s=0; while(n>0) { d=n%10; s=s+(d*d*d); n=n/10; } if(k==s) System.out.println("Armstrong number"); else System.out.println("not Armstrong number"); } }


To find Armstrong number in java?

/*Program to find whether given no. is Armstrong or not. Example : Input - 153 Output - 1^3 + 5^3 + 3^3 = 153, so it is Armstrong no. */ class Armstrong{ public static void main(String args[]){ int num = Integer.parseInt(args[0]); int n = num; //use to check at last time int check=0,remainder; while(num > 0){ remainder = num % 10; check = check + (int)Math.pow(remainder,3); num = num / 10; } if(check == n) System.out.println(n+" is an Armstrong Number"); else System.out.println(n+" is not a Armstrong Number"); } }


Write a c program to find Armstrong number using ifstatement?

#include<stdio.h> int main(){ int num,r,sum,temp; int min,max; printf("Enter the minimum range: "); scanf("%d",&min); printf("Enter the maximum range: "); scanf("%d",&max); printf("Armstrong numbers in given range are: "); for(num=min;num<=max;num++){ temp=num; sum = 0; while(temp!=0){ r=temp%10; temp=temp/10; sum=sum+(r*r*r); } if(sum==num) printf("%d ",num); } return 0; }