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All three refer to a form of power. Active power units use watts, apparent power uses voltamps, and reactive power uses voltampreactives. So, they are Wh, VAh, and VARh. The M is the prefix for Mega, meaning 10^6.
active power,reactive power and apparent power
According to Wikipedia, all forms of power can be expressed in Watts, but typically one expresses only REAL Power in Watts (& Kilowatts).The standard is to express Apparent Power in Volt-Amperes (VA) (& KVA).The kilowatt is the unit of measure for true power; apparent power is measured in volt amperes.However, the volt ampere and the reactive volt ampere (for reactive power) are traditional units, used to help differentiate between apparent, true, and reactive power. SI recognises the watt as the unit for each.
help!
There really is no difference.
Apparent Power=Active Power+Reactive Power or Active Power=VI Cos(Phase Angle) Reactive Power=VI Sin(Phase Angle) Apparent Power= VI
'Active power' (also known as 'true power' and 'real power') is the rate of energy dissipation by the in-phase component of current in an AC circuit, expressed in watts.Active power is the vector-difference between apparent power (measured in volt amperes) and reactive power (measured in reactive volt amperes).Expressed in terms of apparent power: Active Power = Apparent Power x power factor = U I cos (phi)
The ratio of active power (real power) and apparent power is called power factor ( pf ). Power Factor ( pf ) = Active Power / Apparent Power = .................. ( kvar )
The power is the product between the magnitude of voltage and the magnitude of current. Whereas the power factor is a ratio between the active power and the apparent power.
If a load takes 50 kW at a power factor of 0.5 lagging calculate the apparent power and reactive power Answer: Apparent power = Active power / Power Factor In this case, Active power = 50 kW and power factor = 0.5 So Apparent power = 50/0.5 = 100 KVA
Cos phi is a European term used on a motor to differentiate between apparent power (kVA) of an inductive load as compared to the active power (kW) that is really used by the load. Cos phi= active power/apparent power. In North America a more familiar term would be power factor. Power factor = kW/kVA
Electricity has three terms. Active power - Watt. Apparent power VA, reactive power VAR. Watt is known as active output
All three refer to a form of power. Active power units use watts, apparent power uses voltamps, and reactive power uses voltampreactives. So, they are Wh, VAh, and VARh. The M is the prefix for Mega, meaning 10^6.
The equation for power factor is PF = True power in watts/Apparent power in Volt Amps.
Apparent power is the vectorial sum of the true power and reactive power. In this case, the total reactive power is the difference between 7200 var and 3600 var -i.e. 3600 var.So you can now use the equation,(apparent power)2 = (true power)2 + (total reactive power)2,to determine your answer.
The vector-relationship between apparent power, true power, and reactive power is represented by a right-angled triangle, whose hypotenuse represents apparent power and whose adjacent represents true power. Since power factor is defined as 'the ratio of true power to apparent power', you will find that this ratio corresponds to the cosine of the angle between them.
'Active' power describes the rate at which energy is delivered to a load and is permanently lost, and is expressed in watts. 'Reactive' power describes the rate at which energy is alternately stored within a magnetic or electric field and returned to the supply every quarter-cycle, and is expressed in reactive volt amperes.You cannot 'convert' one to the other.'Apparent' power is the vectorial sum of active power and reactive power, and is expressed in volt amperes.