The equation for power factor is PF = True power in watts/Apparent power in Volt Amps.
If a load takes 50 kW at a power factor of 0.5 lagging calculate the apparent power and reactive power Answer: Apparent power = Active power / Power Factor In this case, Active power = 50 kW and power factor = 0.5 So Apparent power = 50/0.5 = 100 KVA
The ratio of true power (measured in watts) to apparent power (measured in volt-amperes) in an AC circuit is known as the power factor. It is a dimensionless number that ranges from 0 to 1 and indicates how effectively electrical power is being converted into useful work output. A power factor of 1 (or 100%) means all the power is being effectively converted to work, while a lower power factor indicates inefficiencies in the system. The relationship can be expressed mathematically as: Power Factor (PF) = True Power (P) / Apparent Power (S).
power factor=real power/apparent power... real power in the sense the capacity of the circuit for performing a work in a particular time..for example the work done by a motor circuit is so and so...real power is what we consume from them... apparent power if the product of the current thro' the circuit and the voltage...it will be always greater than the real power.. if the POWER FACTOR IS 1.0(100%),THEN THE AC POWER IN THE CIRCUIT WILL BE EQUIVALENT TO THE POWER OFFERED BY A DC CIRCUIT....
The power factor is a measure of how effectively electrical power is being converted into useful work output, representing the ratio of real power (measured in watts) to apparent power (measured in volt-amperes). Mathematically, it is expressed as ( \text{PF} = \frac{P}{S} ), where ( P ) is the real power and ( S ) is the apparent power. It is typically represented as a decimal or percentage, with values ranging from 0 to 1 (or 0% to 100%), where a power factor of 1 indicates maximum efficiency.
The apparent answer to the question would be (100 W)/(120 V) = 0.8333 A, assuming that, as a pure resistance load, the light bulb has a power factor close to 1.0.
The decibel (dB) scale is logarithmic. An increase of power by a factor of 10 is an increase of +10 dB. If power increases by a factor of 100, that is equivalent to +20 dB.The decibel (dB) scale is logarithmic. An increase of power by a factor of 10 is an increase of +10 dB. If power increases by a factor of 100, that is equivalent to +20 dB.The decibel (dB) scale is logarithmic. An increase of power by a factor of 10 is an increase of +10 dB. If power increases by a factor of 100, that is equivalent to +20 dB.The decibel (dB) scale is logarithmic. An increase of power by a factor of 10 is an increase of +10 dB. If power increases by a factor of 100, that is equivalent to +20 dB.
The apparent brightness is assigned a unit called "magnitude", abbreviated "m". Lower numbers mean a brighter star. It is a logarithmic scale, such that every 5 numbers represent a factor of 100; a difference of 1m corresponds, approximately, to a factor of 2.5.The apparent brightness is assigned a unit called "magnitude", abbreviated "m". Lower numbers mean a brighter star. It is a logarithmic scale, such that every 5 numbers represent a factor of 100; a difference of 1m corresponds, approximately, to a factor of 2.5.The apparent brightness is assigned a unit called "magnitude", abbreviated "m". Lower numbers mean a brighter star. It is a logarithmic scale, such that every 5 numbers represent a factor of 100; a difference of 1m corresponds, approximately, to a factor of 2.5.The apparent brightness is assigned a unit called "magnitude", abbreviated "m". Lower numbers mean a brighter star. It is a logarithmic scale, such that every 5 numbers represent a factor of 100; a difference of 1m corresponds, approximately, to a factor of 2.5.
2 to the third power x2=highest common factor of 100 and 96=16
"Unity"
Real power = voltage x current x power factor.
The kW rating of a transformer can be calculated by multiplying the kVA rating by the power factor. For example, if the power factor is 0.8, then the kW rating of a 100 kVA transformer would be 80 kW. You can also use the formula: kW = kVA x power factor.
The designation "12V 100VA" indicates that the device operates at a voltage of 12 volts and has a power rating of 100 volt-amperes (VA). The "VA" unit represents apparent power, which is a combination of real power (watts) and reactive power, and is particularly relevant for AC circuits. This means the device can draw up to 100 VA of power, but the actual wattage may vary depending on the power factor of the load. In essence, it specifies the electrical requirements for proper operation.