Want this question answered?
Silver(I) chromate = Ag2CrO4
ksp = [Ca+2][OH-]^2
Two types: silver (Ag+) and chromate (CrO4-2) And within the formula (Ag2CrO4) there are two silver ions and one chromate ion for a total of three ions.
Solubility product constant, Ksp, uses concentrations of soluble (dissolved) substances. A solid is not dissolved.
Silver(I) chromate --Δ--> Chromium(III) oxide + Silver + Oxygen2Ag2CrO4 --Δ--> Cr2O3 + 4Ag + 2.5 O2
Ksp= [Ag]^2 [CrO4] / [Ag2CrO4]
due to the solubility product constant(ksp)
Silver Chromate Ag=Silver CrO4= Chromate(a polyatomic ion)
Silver(I) chromate = Ag2CrO4
ksp = [Ca+2][OH-]^2
Silver chromate is not soluble in water.
Ksp = [Ag+]3[PO43-]
The chromate ion (CrO4-2) has yellow colour so all the chromate compounds including silver chromate is yellow in colour.
Two types: silver (Ag+) and chromate (CrO4-2) And within the formula (Ag2CrO4) there are two silver ions and one chromate ion for a total of three ions.
Solubility product constant, Ksp, uses concentrations of soluble (dissolved) substances. A solid is not dissolved.
No
Silver(I) chromate --Δ--> Chromium(III) oxide + Silver + Oxygen2Ag2CrO4 --Δ--> Cr2O3 + 4Ag + 2.5 O2