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How can we prepare potassium chromate?
To prepare potassium chromate, start by dissolving potassium dichromate in water and then adding potassium hydroxide to adjust the pH. The solution is then heated to evaporate water, leaving behind potassium chromate crystals. Purify the crystals by recrystallization to obtain pure potassium chromate.
What happened when potassium chromate solution was poured to the lead nitrate solution?
A bright yellow precipitate of lead chromate forms when potassium chromate solution is added to lead nitrate solution. This is due to the exchange of ions between the two solutions, resulting in the insoluble compound lead chromate being formed.
Solutions of lead nitrate and potassium dichromate are mixed.?
A double displacement reaction will occur, forming solid lead(II) chromate and soluble potassium nitrate. Lead(II) chromate is a yellow precipitate, while potassium nitrate remains in solution.
How many moles of silver chromate could be formed from 50.00ml of 0.0500m silver nitrate solution and 100.00ml of 0.0600m potassium chromate solution?
To find the limiting reactant, calculate the moles of silver nitrate and potassium chromate. Convert the limiting reactant to moles of silver chromate using the balanced chemical equation. Here, 2 moles of silver nitrate react with 1 mole of potassium chromate to form 2 moles of silver chromate. Calculate the moles of silver chromate that can be formed based on the limiting reactant.
How do you make 0.25N K2CrO4 solution?
To make a 0.25N K2CrO4 solution, you need to first calculate the molecular weight of K2CrO4 (potassium chromate). Then, determine the grams of K2CrO4 needed to make the desired volume of solution at a concentration of 0.25N. Dissolve this amount of K2CrO4 in the required volume of solvent, usually water, to make the final solution.
How can we prepare potassium chromate?
To prepare potassium chromate, start by dissolving potassium dichromate in water and then adding potassium hydroxide to adjust the pH. The solution is then heated to evaporate water, leaving behind potassium chromate crystals. Purify the crystals by recrystallization to obtain pure potassium chromate.
What is the reaction of potassium chromate with barium sulphate?
When potassium chromate reacts with barium sulfate, a precipitation reaction occurs. Barium chromate is formed as a yellow precipitate, while potassium sulfate remains in solution. This reaction can be used to detect the presence of sulfate ions in a solution.
How do you make Copper II Chromate?
Copper(II) chromate can be prepared by reacting a solution of sodium chromate with a solution of copper(II) sulfate. The resulting precipitate is then filtered and dried to obtain solid copper(II) chromate.
What happened when potassium chromate solution was poured to the lead nitrate solution?
A bright yellow precipitate of lead chromate forms when potassium chromate solution is added to lead nitrate solution. This is due to the exchange of ions between the two solutions, resulting in the insoluble compound lead chromate being formed.
Solutions of lead nitrate and potassium dichromate are mixed.?
A double displacement reaction will occur, forming solid lead(II) chromate and soluble potassium nitrate. Lead(II) chromate is a yellow precipitate, while potassium nitrate remains in solution.
What is chloride solution?
This solution contain a specified concentration of sodium chloride.
Write the solubility product expression for silver chromate.?
The solubility product expression for silver chromate (Ag2CrO4) is Ksp = [Ag+]²[CrO4²-], where [Ag+] represents the concentration of silver ions and [CrO4²-] represents the concentration of chromate ions in the saturated solution.
What is the difference between volhard and mohr methods?
The Volhard method is a titration method used to determine the concentration of halide ions in a solution using silver nitrate and potassium chromate as indicators. The Mohr method, on the other hand, is also a titration method used to determine the chloride ions concentration in a solution using silver nitrate and potassium chromate indicators. The key difference lies in the end point detection: Volhard method involves the use of a ferric alum indicator that forms a red-brown precipitate, while the Mohr method involves the formation of a red-brown silver chromate precipitate.
How many moles of silver chromate could be formed from 50.00ml of 0.0500m silver nitrate solution and 100.00ml of 0.0600m potassium chromate solution?
To find the limiting reactant, calculate the moles of silver nitrate and potassium chromate. Convert the limiting reactant to moles of silver chromate using the balanced chemical equation. Here, 2 moles of silver nitrate react with 1 mole of potassium chromate to form 2 moles of silver chromate. Calculate the moles of silver chromate that can be formed based on the limiting reactant.
How do you find the concentration of 3.50g of potassium chromate in 100 ml water?
K2CrO4 Molarity (concentration) = moles of solute/Liters of solution (100 ml = 0.100 Liters ) Find moles K2CrO4 first. 3.50 grams = (1 mole K2CrO4/194.2 grams) = 0.01802 moles K2CrO4 ----------------------------------------------next Molarity = 0.01802 moles K2CrO4/0.100 Liters = 0.180 M K2CrO4 -------------------------
How many ml equals to 20 meq of potassium?
To convert milliequivalents (meq) of potassium to milliliters (ml), you need to know the concentration of the potassium solution being used. For example, in a common potassium chloride solution, 1 meq of potassium is approximately equal to 0.5 ml of a 2 mEq/ml solution. Therefore, 20 meq of potassium would equal about 10 ml in that concentration. Always check the specific concentration of the solution for accurate conversions.
How do you make 0.25N K2CrO4 solution?
To make a 0.25N K2CrO4 solution, you need to first calculate the molecular weight of K2CrO4 (potassium chromate). Then, determine the grams of K2CrO4 needed to make the desired volume of solution at a concentration of 0.25N. Dissolve this amount of K2CrO4 in the required volume of solvent, usually water, to make the final solution.
