alam mo kung ginawa mo ung experiment nung friday sa chem lab hindi mo na itatanong yan
The number of moles of silver chromate formed will depend on the stoichiometry of the reaction between silver nitrate and potassium chromate. You need to know the balanced chemical equation, as well as the exact volumes and concentrations of the silver nitrate and potassium chromate solutions to calculate the number of moles of silver chromate formed.
A double displacement reaction will occur, forming solid lead(II) chromate and soluble potassium nitrate. Lead(II) chromate is a yellow precipitate, while potassium nitrate remains in solution.
When potassium chromate reacts with magnesium nitrate, a double displacement reaction occurs. Potassium nitrate and magnesium chromate are formed as products. This reaction is represented by the following equation: K2CrO4 + Mg(NO3)2 -> MgCrO4 + 2KNO3.
To find the limiting reactant, calculate the moles of silver nitrate and potassium chromate. Convert the limiting reactant to moles of silver chromate using the balanced chemical equation. Here, 2 moles of silver nitrate react with 1 mole of potassium chromate to form 2 moles of silver chromate. Calculate the moles of silver chromate that can be formed based on the limiting reactant.
The ionic equation for the reaction between silver nitrate (AgNO3) and potassium chromate (K2CrO4) is: Ag+ + 2NO3- + 2K+ + CrO42- -> Ag2CrO4(s) + 2KNO3 This reaction forms silver chromate (Ag2CrO4) as a solid precipitate, with potassium nitrate (KNO3) remaining in solution.
The number of moles of silver chromate formed will depend on the stoichiometry of the reaction between silver nitrate and potassium chromate. You need to know the balanced chemical equation, as well as the exact volumes and concentrations of the silver nitrate and potassium chromate solutions to calculate the number of moles of silver chromate formed.
A double displacement reaction will occur, forming solid lead(II) chromate and soluble potassium nitrate. Lead(II) chromate is a yellow precipitate, while potassium nitrate remains in solution.
When potassium chromate is treated with barium nitrate, a double displacement reaction occurs. Barium chromate and potassium nitrate are formed as products. A yellow precipitate of barium chromate is observed in the reaction mixture.
by the reaction of lead nitrate with potassium chromate or potassium dichromate
When potassium chromate reacts with magnesium nitrate, a double displacement reaction occurs. Potassium nitrate and magnesium chromate are formed as products. This reaction is represented by the following equation: K2CrO4 + Mg(NO3)2 -> MgCrO4 + 2KNO3.
To find the limiting reactant, calculate the moles of silver nitrate and potassium chromate. Convert the limiting reactant to moles of silver chromate using the balanced chemical equation. Here, 2 moles of silver nitrate react with 1 mole of potassium chromate to form 2 moles of silver chromate. Calculate the moles of silver chromate that can be formed based on the limiting reactant.
When potassium chromate (K₂CrO₄) reacts with strontium nitrate (Sr(NO₃)₂), a double displacement reaction occurs, resulting in the formation of strontium chromate (SrCrO₄) and potassium nitrate (KNO₃). The balanced chemical equation for this reaction is: [ K_2CrO_4 + Sr(NO_3)_2 \rightarrow SrCrO_4 + 2 KNO_3 ] Strontium chromate is a yellow precipitate, indicating the occurrence of the reaction.
The ionic equation for the reaction between silver nitrate (AgNO3) and potassium chromate (K2CrO4) is: Ag+ + 2NO3- + 2K+ + CrO42- -> Ag2CrO4(s) + 2KNO3 This reaction forms silver chromate (Ag2CrO4) as a solid precipitate, with potassium nitrate (KNO3) remaining in solution.
When sodium chromate and lead nitrate are mixed, a yellow precipitate of lead chromate is formed, along with sodium nitrate remaining in solution.
In order to form a potassium nitrate solution, the ionic bond between potassium ions and nitrate ions in the solid potassium nitrate compound needs to be broken. This allows the potassium and nitrate ions to separate and become surrounded by water molecules, resulting in the formation of a potassium nitrate solution.
The conductivity of potassium nitrate depends on its concentration in solution. Generally, potassium nitrate is a strong electrolyte, meaning it dissociates completely into ions in solution and conducts electricity well.
Just potassium nitrate in water. Aqueous stands for anything with water, so if you take dry potassium nitrate and add some water to it until it dissolves, you have made an aqueous solution of potassium nitrate.