What is the Lewis structure for TeF6?

Answer 1

There are 42+5+1 valence electrons = 48

6 initial bonds, leaving 36 more electrons to distribute. These go around the F atoms.

so P as the central atom, and 6 single bonded F atoms around it. Structure is octahedral.

Answer 2

The Lewis structure for TeF6 (tellurium hexafluoride) consists of a central tellurium atom bonded to six fluorine atoms. Tellurium has 6 valence electrons, and each fluorine contributes one valence electron, totaling 12 electrons. The structure will have 12 total valence electrons arranged so that each fluorine atom is bonded to the tellurium atom with single bonds.

Answer 3

F(6 valance electrons)\ /F(6 valance electrons)

F(6 valance electrons)-Te-F(6 valance electrons)

F(6 valance electrons)/ \F(6 valance electrons)

68 electrons with 20 left over.

Te is a group 6

F is a group 7 with 6 times so that is 6+6(7)=68

Answer 4

H H

.. ..

:C: :C:

.. \ / ..

:F-----Te---------------------F:

.. / .. ..

H:C:H

..

H

(ch3)- so (ch3)4= 4- charge

Te +6 ion and F2- ions = 4+ charge

Te has 6 total valence electron pairs, 5 bonding, 1 not, VSEPR= AX5E, >90 degrees, square pyramidal.

Answer 5

S is the central atom with single bonds connecting it to 6 Fs with 3 lone pairs on each F.

Answer 6

trigonal pyramidal (AX3N), The PF3 bond angle will be about 109 degrees since it has a trigonal pyramidal molecular geometry.

Answer 7

Si is the central atom connected to 6 fluorine atoms with 3 sets of lone pairs on each fluorine atom.

Answer 8

It is Triangular Bipyrcamidal with a SP3d hybridization. A Lewis dot diagram would be drawn as phosphorus as the central atom, then the 5 fluorines surrounding the central atom.

Answer 9

AsF6-1

Answer 10

Pf4