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What is the Slope-Intercept inequality for the graph 3 2 and -3 -6?
Wiki User
∙ 13y ago
y=mx+b
m = slope
b = y-intercept slope = (y1-y2)/(x1-x2)
slope = (2--6)/(3--2)
slope = 8/5
2=(8/5)3+b
2=24/5+b
5/12=b
y=8/5x+5/12
Wiki User
∙ 13y ago
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How do you graph inequalities?
Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
Write the equation in slopeintercept form of the line that has a slope of 3 and contains the point 2 5?
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
To graph the inequality is y less than or equal to negative 5x plus 3 you would draw a solid line?
FALSE
How can i graph c -4 2 and slope 3 2?
You can graph X -4 2 and slope 3 2 by first finding the values of X and Y and then using those values to sketch your graph.
Is 2 a solution to the inequality x 3?
Yes, It is a solution (a+)
How do you graph an inequality?
Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
How do you graph inequalities?
Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
Write the equation in slopeintercept form of the line that has a slope of 2 and contains the point 3 7?
y = 2x + 1.
How do you solve an graph the inequality 2x is greater than or equal to -6?
8
Solve the inequality 3 -2 x 7.?
The above is not an inequality as stated.
How would you graph 3 to -2?
5
Write the equation in slopeintercept form of the line that has a slope of 3 and contains the point 2 5?
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
To graph the inequality is y less than or equal to negative 5x plus 3 you would draw a solid line?
FALSE
Does raising each side of a compound inequality to a negative exponent flip the signs of the inequality?
Yes, taking the reciprocal (raising each side to the -1 power) of each side of a compound inequality can flip the signs of the inequality. This can be useful when you have an inequality with 'x' in the quotient. Taking the reciprocal of each side can be a more direct way of solving the inequality than multiplying each side by 'x'. The following is an example: | 2/x - 2 | < 4 Following the rules for an absolute value inequality we obtain the following compound inequality: -4 < 2/x - 2 < 4 Next add 2 to each side to get 'x' by itself. -2 < 2/x < 6 Here we can multiply each side by 'x' to deal with 'x' in the quotient, but instead we'll raise each side to an exponent of (-1). We obtain the following: -1/2 > x/2 > 1/6 (Notice the signs flip.) We rewrite as: 1/6 < x/2 < -1/2 Next multiply each side by 2 to get 'x' by itself. 1/3 < x < -1 Our solution set is the following: {x: x > 1/3 OR x < -1} Which is the union of the two infinite intervals (-infinity, -1) AND (1/3, infinity). For these types of inequalities if we believe that perhaps we've made a mistake or that our signs are wrong, we can check our work by plugging in some values for x and evaluating the inequality to see whether or not the statement is true. It helps to graph the inequality on a line and by evaluating x at different points on the graph of our inequality for the values of x that make our statement true; we can see exactly what the inequality looks like. For example, we will evaluate the original inequality with points that are less than -1, in between -1 and 1/3, and greater than 1/3. We'll try x = -2 first, |2/(-2) - 2| < 4 |-1-2| < 4 |-3| < 4 -(-3) < 4 3 < 4 True, our solution: x < -1 holds true. Next we'll solve for x = -1/2, |2/(-1/2) - 2| < 4 |-4 - 2| < 4 |-6| < 4 -(-6) < 4 6 < 4 False, this point is not on the graph of our inequality, so we know that the sign of our solution: x < -1 is going in the right direction and holds true. Next we'll solve for x = 1/4, |2/(1/4) -2| < 4 |8 - 2| < 4 |6| < 4 6 < 4 False, this point is not on the graph of our inequality, so it looks like our second solution x > 1/3 is accurate and our sign is most likely going in the correct direction. Lastly, we'll evaluate for a point x > 1/3 and this point should be on the graph of our inequality. |2/(1) - 2| < 4 |2-2| < 4 |0| < 4 0 < 4 True, we've proved that our solution x > 1/3 holds true for the graph of this inequality and that the sign for our solution is going in the correct direction. In fact if we substitute a very large number in for x, say 1,000 we'll notice the left side of our statement gets closer and closer to 2 as x approaches infinity. |2/(1000) -2| < 4 |-1.998| < 4 -(-1.998) < 4 1.998 < 4 True, we know for certain that the solution x > 1/3 holds true for all values of x to infinity. Our solution set again is, {x: x < -1 or x > 1/3} The union of the two infinite intervals is (-infinity, -1) and (1/3, infinity).
How can you graph an inequality?
You have to graph an inequality on a number line. For example, x>3.The number 3 on the number line gets an open circle around it, and a line is extended to all the other possible equations.There is an open circle if it is a "greater than or less than" sign, and there is a shaded circle if there is "greater than or equal to, or a less than or equal to" sign.
Is 2 a solution of the inequality 2x 5 9?
2 is a solution of the equation, but not if it's an inequality.
Is 2 a solution to the inequality x 3?
Yes, It is a solution (a+)
