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It will take about 4 hours and 51 minutes of total driving time at a constant 70 mph. Add some time for stops and delays.

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15y ago

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How long does it take to travel 4.2 billion miles at 340 MPH?

Speed = Distance/Time Time = Distance/Speed Time = 4 200 000 000/340 Length of time = 12 352 941.18 hours.


How long will it take to travel 340 miles?

At 60 MPH average, about 5 hr 40 min.


What is the average speed of a car if the total distance was 340 mi and the total time was 4.2 hours?

340 miles / 4.2 hours = 80.95 MPH


How long does it take to drive 340 miles at fifty miles per hour?

Time taken = Distance ÷ Speed (or Velocity) To drive 340 miles at 50 mph would take :- 340 ÷ 50 = 6.8 hours = 6 hours 48 mins.


Time it takes to travel 800 miles at 15 mph?

It would take 53 hrs. 20 mins. to travel 800 miles at 15 mph.


How long does it take to drive 340 miles?

To cover the 340 miles will require at least 5 hoursand 13 minutes of driving time if you maintain a steady 65 mph. You will have to add time for stops, detours and other delays.


How long would it take to drive 340 miles at 70 mph?

To find the time taken in travel, divide an object's distance by its speed. In this instance, 340 / 70 = 4.857142 recurring (that is, 4.857142857142... or 4 and six sevenths) hours. The formula D=rt, where D is distance, r is rate (speed), and t is time, is quite useful later in life, so you should remember it.340 miles/70 miles per hour = 340 miles/1.167 miles per minute = 291 minutes = 4 hours 51 minutes.


Travel time for 82.64 miles at 65 mph?

76.3 minutes


Time to travel .78 miles at 65 mph?

About 43 seconds.


How fast in mph is 340 kph?

340 kph = 211.26 mph


What is the mph to travel 52.28 miles in 3 hours?

Speed = Distance/Time = 52.28/3 mph = 17.4166... mph


How long to travel 2500 miles at 5 miles per hour?

Speed is distance/time. You are given that the speed = 5 mph and the distance is 2500 miles.So, 5 mph = 2500 miles / time , or 5 mph * time = 2500 miles. Divide 2500 miles by 5 mph, and you get 500 hours.