CH3COOH + NaOH --> CH3COONa + H2O
Or better the ionic equation in water:
CH3COOH + OH- --> CH3COO- + H2O
[Na+ ions are left out of the equation because they don't take part in this reaction: it stays unchanged in solution]
HCH3COO+NaOH=H20+NaCH3COO
1 HCl + 1 NaOH ---> 1 NaCl + 1 H(OH)
HCl + NaOH --> NaCl + H2O
water and the sodium salt
Sodium hydroxide does not react with hydrogen gas.
HCH3COO+NaOH=H20+NaCH3COO
The chemical equation is:C6H8O7 + 3 NaOH = C6H5O7Na3 + 3 H2O
1 HCl + 1 NaOH ---> 1 NaCl + 1 H(OH)
HCl + NaOH --> NaCl + H2O Just a double replacement reaction between OH- and Cl-.
water and the sodium salt
HCl + NaOH --> NaCl + H2O
NaOH + CH3COOH = CH3COONa + H2O Good Luck !
Here are only two reactants.
PbCrO4 + 4NaOH = Na2CrO4 + Na2PbO2 + 2H2O
Sodium hydroxide does not react with hydrogen gas.
NaOH + HCl >> NaCl + H2O
HCl + NaOH = H2O + NaCl is already balanced.