NaOH+H3COOC2H5 --> CH3COONA+C2H5OH
To make the components more clear.
(Na-OH)+(H3COO-C2H5) --> (CH3COO-NA)+(C2H5-OH)
Sodium Acetate Can be fond in 2 forms. Either anhydrous or trihydrate. Oxidation reaction with anhydrous form is easier than trihydrate form. First form has reaction similar to that of Oxidation of Acetic Acid. Trihydrate form is a bit more complex and I'm still loking into it
No visible reaction. It stays clear. No Odor either.
By the reaction of acetone with I2 and NaOH (iodoform reaction)
There is no reaction between them: They only 'could exchange' the H+ and Na+ ions but the products are identical to the reactants.CH3COOH + CH3COONa --> CH3COONa + CH3COOH
To make ethyl acetate, react ethanol with ethanoic acid in the presence of concentrated sulphuric acid. Another method is by preparing industrially using the Tishchenko reaction by combining two equivalents of acetaldehyde in the presence of an alkoxide catalyst.
Sodium Acetate Can be fond in 2 forms. Either anhydrous or trihydrate. Oxidation reaction with anhydrous form is easier than trihydrate form. First form has reaction similar to that of Oxidation of Acetic Acid. Trihydrate form is a bit more complex and I'm still loking into it
No visible reaction. It stays clear. No Odor either.
If they are charged particles formed during a reaction the immediately form ethyl alcohol but the don't exist as free units, the reaction for formation of ethyl alcohol is as follows, C2H5-Cl + NaOH = C2H5-OH + NaCl
When sodium acetate react with soda lime it produce sodium carbonate and methane gas. CH3COONa + NaOH---------- NaCO3 + CH4
By the reaction of acetone with I2 and NaOH (iodoform reaction)
There is no reaction between them: They only 'could exchange' the H+ and Na+ ions but the products are identical to the reactants.CH3COOH + CH3COONa --> CH3COONa + CH3COOH
H3NSO3 + NaOH = NaSO3NH2 + H2O
NaOH + HCl --> NaCl + H2O
HOC6H4COOH + NaOH = HOC6H4COONa + H2O
oxidation-reductionWhat type of a reaction occurs when a sodium hydroxide solution is mixed with an acetic acid solution?The answer above is wrong. The correct answer is acid-base neutralization
This reaction is:2 F2 + 4 NaOH = 4 NaF + 2 H2O + O2
It doesn't need balancing - it's already balanced. NaHCO3 + NaOH → Na2CO3 + H2O