The reaction of acetic acid and sodium hydroxide will form sodium acetate and water. The chloroform is not involved in the reaction and will remain unchanged. The balanced chemical equation for the reaction is:
CH3COOH (acetic acid) + NaOH (sodium hydroxide) -> CH3COONa (sodium acetate) + H2O (water)
The reaction between sodium hydroxide (NaOH) and acetic acid (CH3COOH) forms sodium acetate (CH3COONa) and water (H2O). The balanced chemical equation is: CH3COOH + NaOH -> CH3COONa + H2O.
C_2_H_4_O_2_ (aq) + OH^-^ (aq) --> C_2_H_3_O_2_^-^ (aq) + H_2_O (l)
The complete molecular equation for the reaction between acetic acid (CH3COOH) and sodium hydroxide (NaOH) is: CH3COOH (aq) + NaOH (aq) -> CH3COONa (aq) + H2O (l)
The chemical equation for acetic acid (CH3COOH) reacting with lithium hydroxide (LiOH) to produce water (H2O) and lithium acetate (LiCH3COO) can be represented as: CH3COOH + LiOH → H2O + LiCH3COO
CH3COOH + OH ---> CH3COO + H2O CH3COOH stays as a molecule because it is a weak acid
The reaction between sodium hydroxide (NaOH) and acetic acid (CH3COOH) forms sodium acetate (CH3COONa) and water (H2O). The balanced chemical equation is: CH3COOH + NaOH -> CH3COONa + H2O.
C_2_H_4_O_2_ (aq) + OH^-^ (aq) --> C_2_H_3_O_2_^-^ (aq) + H_2_O (l)
The complete molecular equation for the reaction between acetic acid (CH3COOH) and sodium hydroxide (NaOH) is: CH3COOH (aq) + NaOH (aq) -> CH3COONa (aq) + H2O (l)
The chemical equation for acetic acid (CH3COOH) reacting with lithium hydroxide (LiOH) to produce water (H2O) and lithium acetate (LiCH3COO) can be represented as: CH3COOH + LiOH → H2O + LiCH3COO
CH3COOH + OH ---> CH3COO + H2O CH3COOH stays as a molecule because it is a weak acid
The reaction between aqueous acetic acid (CH3COOH) and aqueous sodium hydroxide (NaOH) forms water (H2O) and sodium acetate (CH3COONa). The balanced chemical equation is: CH3COOH + NaOH -> H2O + CH3COONa
CH3COOH+NH4OH turns into H2O+CH3COONH4 have fun with chem
The balanced chemical equation for neutralizing aqueous acetic acid (HC2H3O2) with aqueous potassium hydroxide (KOH) is: HC2H3O2 + KOH → KC2H3O2 + H2O This reaction forms potassium acetate (KC2H3O2) and water (H2O) when acetic acid reacts with potassium hydroxide in a 1:1 molar ratio.
The chemical equation for the reaction between ethanoic acid (acetic acid) and sodium hydroxide is: CH3COOH + NaOH → CH3COONa + H2O This reaction is a neutralization reaction that forms sodium acetate and water.
The preparation equation depends on the route by which this compound is prepared. A simple route is neutralization of acetic acid with potassium hydroxide: KOH + CH3COOH --> H2O + K+CH3COO-
The balanced chemical equation for the reaction between acetic acid (CH3COOH) and aluminum hydroxide (Al(OH)3) to form water and aluminum acetate (Al(CH3COO)3) is: 2CH3COOH + 3Al(OH)3 -> 3H2O + Al(CH3COO)3
The balanced equation for the reaction between acetic acid (HC2H3O2) and sodium hydroxide (NaOH) is: HC2H3O2 + NaOH → NaC2H3O2 + H2O