The balanced chemical equation for the reaction between acetic acid (CH3COOH) and aluminum hydroxide (Al(OH)3) to form water and aluminum acetate (Al(CH3COO)3) is:
2CH3COOH + 3Al(OH)3 -> 3H2O + Al(CH3COO)3
When aluminium hydroxide reacts with nitric acid, aluminum nitrate and water are formed. The balanced chemical equation for this reaction is: 2Al(OH)3 + 6HNO3 → 2Al(NO3)3 + 6H2O
The balanced chemical equation for the formation of rubidium hydroxide from rubidium oxide is: 2 Rb2O + 2 H2O → 4 RbOH
The balanced chemical equation is: 2HNO3 + Al2O3 --> 2Al(NO3)3 + 3H2O
The word equation for the reaction between aluminium hydroxide and sulphuric acid is: aluminium hydroxide + sulphuric acid → aluminium sulphate + water.
The word equation for this reaction is: aluminium hydroxide + sulfuric acid → aluminium sulfate + water.
When aluminium hydroxide reacts with nitric acid, aluminum nitrate and water are formed. The balanced chemical equation for this reaction is: 2Al(OH)3 + 6HNO3 → 2Al(NO3)3 + 6H2O
The balanced chemical equation for the formation of rubidium hydroxide from rubidium oxide is: 2 Rb2O + 2 H2O → 4 RbOH
The balanced chemical equation is: 2HNO3 + Al2O3 --> 2Al(NO3)3 + 3H2O
The word equation for the reaction between aluminium hydroxide and sulphuric acid is: aluminium hydroxide + sulphuric acid → aluminium sulphate + water.
2Al + N2 ----> 2AlN
The word equation for this reaction is: aluminium hydroxide + sulfuric acid → aluminium sulfate + water.
Aluminium Sulphate and potassium hydroxide. Al2(SO4)3 + 6KOH = 3K2(SO4) + 2Al(OH)3
Iron(III) hydroxide is 'Fe(OH)3 ' As you have given it , it is incorrect. FeO(s) + 2H2O(l) = Fe(OH)3 + (3/4)H2(g) 4FeO(s) + 8H2O(l) = 4Fe(OH)3(aq)+ 2H2(g) Done!!!!!
Simplified. 2NaOH + H2SO4 -> Na2SO4 + 2H2O
The chemical equation is:2 Al(OH)3 = Al2O3 + 3 H2O
The balanced chemical equation for the reaction between NaOH (sodium hydroxide) and tartaric acid (C4H6O6) is: 2NaOH + H2C4H4O6 -> 2H2O + Na2C4H4O6
Ca(NO3)2 + 2KI ----> CaI2 + 2KNO3