The word equation for this reaction is: aluminium hydroxide + sulfuric acid → aluminium sulfate + water.
The word equation for the reaction between aluminium hydroxide and sulphuric acid is: aluminium hydroxide + sulphuric acid → aluminium sulphate + water.
The word equation for aluminum sulfate is: aluminum sulfate + water → aluminum hydroxide + sulfuric acid.
The word equation for the reaction of sulfuric acid and sodium hydroxide is: sulfuric acid + sodium hydroxide → sodium sulfate + water.
sulphuric acid + lithium hydroxide ---> lithium sulphate + water
H2SO4 + 2 NaOH --> Na2SO4 + 2 H2O. Sulfuric Acid + Sodium Hydroxide --> Sodium Sulfate + Water.
The word equation for the reaction between aluminium hydroxide and sulphuric acid is: aluminium hydroxide + sulphuric acid → aluminium sulphate + water.
The word equation for aluminum sulfate is: aluminum sulfate + water → aluminum hydroxide + sulfuric acid.
The word equation for the reaction of sulfuric acid and sodium hydroxide is: sulfuric acid + sodium hydroxide → sodium sulfate + water.
sulphuric acid + lithium hydroxide ---> lithium sulphate + water
H2SO4 + 2 NaOH --> Na2SO4 + 2 H2O. Sulfuric Acid + Sodium Hydroxide --> Sodium Sulfate + Water.
The neutralization reaction between sulfuric acid (H2SO4) and sodium hydroxide (NaOH) can be represented by the following equation: H2SO4 + 2NaOH → Na2SO4 + 2H2O. In this reaction, sulfuric acid reacts with sodium hydroxide to form sodium sulfate and water.
Sulfuric acid (H2SO4) reacts with sodium hydroxide (NaOH) to form sodium sulfate (Na2SO4) and water (H2O). The balanced equation is: H2SO4 + 2NaOH → Na2SO4 + 2H2O.
Sulfuric acid + Beryllium Hydroxide → Berylium Sulfate + 2 Water H2SO4 + Be(OH)2 → Be SO4 + 2H2O
The balanced equation for the reaction between copper(II) hydroxide (Cu(OH)2) and sulfuric acid (H2SO4) is Cu(OH)2 + H2SO4 → CuSO4 + 2H2O.
sulphuric acid
sulphuric acid+lithium hydroxide=lithium sulphate+water
In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.