Iron(III) hydroxide is 'Fe(OH)3 '
As you have given it , it is incorrect.
FeO(s) + 2H2O(l) = Fe(OH)3 + (3/4)H2(g)
4FeO(s) + 8H2O(l) = 4Fe(OH)3(aq)+ 2H2(g)
Done!!!!!
Fe(NO3)2 + 2NaOH-->Fe(OH)2 + 2NaNO3 (Assuming Fe is Fe (II))
The balanced equation for iron sulfate (FeSO4) reacting with sodium hydroxide (NaOH) to form iron hydroxide (Fe(OH)3) and sodium sulfate (Na2SO4) is: FeSO4 + 2NaOH → Fe(OH)3 + Na2SO4
The chemical equation when sodium hydroxide is added to iron(II) is: Fe(OH)2 (iron(II) hydroxide) + 2NaOH (sodium hydroxide) -> Fe(OH)2 + 2NaOH.
Iron chloride and sodium hydroxide will make iron hydroxide and sodium chloride. For Iron II chloride the equation is: 2NaOH(aq) + FeCl2(aq) --> 2NaCl(aq) + Fe(OH)2(S). For Iron III chloride the equation is: 3NaOH(aq) + FeCl3(aq) --> 3NaCl(aq) + Fe(OH)3(S).
The balanced equation for the reaction between phenol (C6H5OH), sodium hydroxide (NaOH), and iron(III) chloride (FeCl3) is: C6H5OH + NaOH + FeCl3 → C6H4(OH)Na + FeCl2 + H2O
Fe(NO3)2 + 2NaOH-->Fe(OH)2 + 2NaNO3 (Assuming Fe is Fe (II))
The balanced equation for iron sulfate (FeSO4) reacting with sodium hydroxide (NaOH) to form iron hydroxide (Fe(OH)3) and sodium sulfate (Na2SO4) is: FeSO4 + 2NaOH → Fe(OH)3 + Na2SO4
Yellow ppt. of iron???? I think you mean ' iron(III) hydroxide'. which is yellow/brown in colour. Here is a balanced equation. Fe(NO3)3(aq) + 3NaOH(aq) = 3NaNO3(aq)+ Fe(OH)3(s); NB Iron salts in oxidation state '3' (III) are yellow/orange/brown in colour. Compare to iron salts in oxidation state '2' (II) , which are (pale) green in colour.
When iron (III) nitrate reacts with sodium hydroxide, it forms iron (III) hydroxide and sodium nitrate. The balanced chemical equation for this reaction is: Fe(NO3)3 + 3NaOH → Fe(OH)3 + 3NaNO3. Iron (III) hydroxide is a brown solid that forms as a precipitate in this reaction.
The chemical equation when sodium hydroxide is added to iron(II) is: Fe(OH)2 (iron(II) hydroxide) + 2NaOH (sodium hydroxide) -> Fe(OH)2 + 2NaOH.
Iron Chloride + Sodium Hydroxide ------> Iron Hydroxide + Sodium Chloride Balanced reaction equations: FeCl3 + 3NaOH ------> Fe(OH)3 + 3NaCl or FeCl2 + 2NaOH ------> Fe(OH)2 + 2NaCl because iron can be either Iron(III)[Fe3+] or Iron(II)[Fe2+]
Iron chloride and sodium hydroxide will make iron hydroxide and sodium chloride. For Iron II chloride the equation is: 2NaOH(aq) + FeCl2(aq) --> 2NaCl(aq) + Fe(OH)2(S). For Iron III chloride the equation is: 3NaOH(aq) + FeCl3(aq) --> 3NaCl(aq) + Fe(OH)3(S).
The chemical formula (not equation) is Fe(OH)2.
The balanced chemical equation for the rusting of iron is: 4Fe + 6H2O + 3O2 -> 4Fe(OH)3
The balanced equation for the reaction between phenol (C6H5OH), sodium hydroxide (NaOH), and iron(III) chloride (FeCl3) is: C6H5OH + NaOH + FeCl3 → C6H4(OH)Na + FeCl2 + H2O
The balanced chemical equation for the reaction between iron (III) nitrate and sodium chloride is: 2Fe(NO₃)₃ + 6NaCl → 2FeCl₃ + 6NaNO₃.
The balanced chemical equation for the reaction between iron and magnesium chloride is: 2Fe + 3MgCl2 -> 3Mg + 2FeCl3