The chemical formula (not equation) is Fe(OH)2.
The chemical name for Fe(OH)2 is iron(II) hydroxide.
The chemical equation when sodium hydroxide is added to iron(II) is: Fe(OH)2 (iron(II) hydroxide) + 2NaOH (sodium hydroxide) -> Fe(OH)2 + 2NaOH.
Iron (II) hydroxide has a chemical formula Fe(OH)2. To find the percent of iron in iron (II) hydroxide, you need to calculate the molar mass of iron (Fe) and divide it by the molar mass of the compound Fe(OH)2, then multiply by 100 to get the percentage. The percent of iron in iron (II) hydroxide is approximately 69.9%.
After the reaction of iron with an acid a salt is formed, not a hydroxide.
The products of the reaction between iron II sulfate and sodium hydroxide are iron II hydroxide and sodium sulfate. The balanced chemical equation for this reaction is FeSO4 + 2NaOH → Fe(OH)2 + Na2SO4.
I believe this is the correct formula: Fe(OH)2
Iron (II) hydroxide and sodium sulfate are formed when iron (II) sulfate is mixed with sodium hydroxide. Iron (II) hydroxide is a green precipitate that forms in the reaction.
The balanced chemical formula for the reaction between iron(II) sulfate and sodium hydroxide is: FeSO4 + 2NaOH -> Fe(OH)2 + Na2SO4.
It depends on whether it is iron (II) hydroxide or iron (III) hydroxide.
For the chemical equation, simply replace the name of each compound with its chemical formula: NaOH + FeCl2 --> Fe(OH)2 + NaCl
dark green (but orange - brown if left standing)
The formula for Iron(II) hydroxide is Fe(OH)2. It is an inorganic compound that consists of one iron(II) ion bonded to two hydroxide ions.