dark green (but orange - brown if left standing)
When copper sulfate and sodium hydroxide are mixed, a blue precipitate of copper hydroxide is formed. This is because the hydroxide ions from sodium hydroxide react with the copper ions from copper sulfate to form the insoluble copper hydroxide. The net ionic equation for this reaction is Cu^2+ (aq) + 2OH^- (aq) → Cu(OH)2 (s).
When copper sulfate and sodium hydroxide are heated together, a series of chemical reactions occur. Initially, the copper sulfate decomposes to form copper oxide, water, and sulfur dioxide gas. Then, the copper oxide reacts with sodium hydroxide to form a blue precipitate of copper hydroxide.
Sodium hydroxide turns red litmus paper blue.
Sodium hydroxide is a strong base and will turn red litmus paper blue. This color change occurs due to the high concentration of hydroxide ions present in the sodium hydroxide solution, which react with the indicator dye in the litmus paper, causing the color change.
The products of the reaction between iron II sulfate and sodium hydroxide are iron II hydroxide and sodium sulfate. The balanced chemical equation for this reaction is FeSO4 + 2NaOH → Fe(OH)2 + Na2SO4.
When copper sulfate is added to sodium hydroxide, a blue precipitate of copper hydroxide is formed. The color change observed is from the initial blue color of copper sulfate to the blue precipitate of copper hydroxide.
this makes sodium sulphate and CO2
No amount of sodium sulphate can be formed from sodium hydroxide alone, because sodium sulfate contains sulfur and sodium hydroxide does not. By neutralization with sulphuric acid, one formula unit of sodium sulphate can be formed from two moles of sodium hydroxide, according to the equation 2 NaOH + H2SO4 -> Na2SO4 + 2 H2O.
If you add copper sulfate to sodium hydroxide, a double displacement reaction will occur. The copper sulfate will react with the sodium hydroxide to form copper hydroxide, which is a blue solid, and sodium sulfate, which is a soluble compound. This reaction is often used in qualitative analysis to test for the presence of copper ions.
Iron (II) hydroxide and sodium sulfate are formed when iron (II) sulfate is mixed with sodium hydroxide. Iron (II) hydroxide is a green precipitate that forms in the reaction.
You would need to add Sulphuric acid to make Sodium Sulphate + Water :)
When copper sulfate and sodium hydroxide are mixed, a blue precipitate of copper hydroxide is formed. This is because the hydroxide ions from sodium hydroxide react with the copper ions from copper sulfate to form the insoluble copper hydroxide. The net ionic equation for this reaction is Cu^2+ (aq) + 2OH^- (aq) → Cu(OH)2 (s).
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Nowhere. I assume you are talking about mixing solutions. The sodium ions and sulpahate ions remain in solution.
The reaction between sodium hydroxide and copper sulfate will result in the formation of sodium sulfate and copper hydroxide. The products of this reaction will be a blue precipitate of copper hydroxide and a solution of sodium sulfate.
In the balanced equation CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4, copper sulfate (CuSO4) is a reactant. It reacts with sodium hydroxide (NaOH) to form copper hydroxide (Cu(OH)2) and sodium sulphate (Na2SO4).
Biuret reagent is made up of sodium hydroxide and copper sulphate.