Iron (II) hydroxide has a chemical formula Fe(OH)2. To find the percent of iron in iron (II) hydroxide, you need to calculate the molar mass of iron (Fe) and divide it by the molar mass of the compound Fe(OH)2, then multiply by 100 to get the percentage. The percent of iron in iron (II) hydroxide is approximately 69.9%.
Iron (II) hydroxide and sodium sulfate are formed when iron (II) sulfate is mixed with sodium hydroxide. Iron (II) hydroxide is a green precipitate that forms in the reaction.
The chemical name for Fe(OH)2 is iron(II) hydroxide.
The formula is Fe(OH)2
After the reaction of iron with an acid a salt is formed, not a hydroxide.
The chemical equation when sodium hydroxide is added to iron(II) is: Fe(OH)2 (iron(II) hydroxide) + 2NaOH (sodium hydroxide) -> Fe(OH)2 + 2NaOH.
Iron (II) hydroxide and sodium sulfate are formed when iron (II) sulfate is mixed with sodium hydroxide. Iron (II) hydroxide is a green precipitate that forms in the reaction.
It depends on whether it is iron (II) hydroxide or iron (III) hydroxide.
The chemical name for Fe(OH)2 is iron(II) hydroxide.
The products of the reaction between iron II sulfate and sodium hydroxide are iron II hydroxide and sodium sulfate. The balanced chemical equation for this reaction is FeSO4 + 2NaOH → Fe(OH)2 + Na2SO4.
dark green (but orange - brown if left standing)
The formula for Iron(II) hydroxide is Fe(OH)2. It is an inorganic compound that consists of one iron(II) ion bonded to two hydroxide ions.
The formula is Fe(OH)2
Fe(OH)2 is named iron(II) hydroxide. It can also be named ferrous hydroxide.
After the reaction of iron with an acid a salt is formed, not a hydroxide.
The chemical equation when sodium hydroxide is added to iron(II) is: Fe(OH)2 (iron(II) hydroxide) + 2NaOH (sodium hydroxide) -> Fe(OH)2 + 2NaOH.
The dark green precipitate formed when sodium hydroxide is added to iron II compounds is iron II hydroxide. When left standing, the iron II hydroxide undergoes further oxidation to form iron III hydroxide, which is orange-brown in color. This change in color is due to the conversion of iron II to iron III within the precipitate.
it is a compound!!