The formula is Fe(OH)2
The formula of iron II hydroxide is Fe (OH) 2
The balanced chemical formula for the reaction between iron(II) sulfate and sodium hydroxide is: FeSO4 + 2NaOH -> Fe(OH)2 + Na2SO4.
The products of the reaction between iron II sulfate and sodium hydroxide are iron II hydroxide and sodium sulfate. The balanced chemical equation for this reaction is FeSO4 + 2NaOH → Fe(OH)2 + Na2SO4.
dark green (but orange - brown if left standing)
Mercury (I) Hydroxide Hg OH2 (2 is subscript) Mercury(II) Hydroxide Hg (OH)2
The formula is Fe(OH)2
The formula of iron II hydroxide is Fe (OH) 2
Iron (II) hydroxide has a chemical formula Fe(OH)2. To find the percent of iron in iron (II) hydroxide, you need to calculate the molar mass of iron (Fe) and divide it by the molar mass of the compound Fe(OH)2, then multiply by 100 to get the percentage. The percent of iron in iron (II) hydroxide is approximately 69.9%.
I believe this is the correct formula: Fe(OH)2
The chemical formula (not equation) is Fe(OH)2.
Iron (II) hydroxide and sodium sulfate are formed when iron (II) sulfate is mixed with sodium hydroxide. Iron (II) hydroxide is a green precipitate that forms in the reaction.
It depends on whether it is iron (II) hydroxide or iron (III) hydroxide.
The balanced chemical formula for the reaction between iron(II) sulfate and sodium hydroxide is: FeSO4 + 2NaOH -> Fe(OH)2 + Na2SO4.
The chemical name for Fe(OH)2 is iron(II) hydroxide.
The products of the reaction between iron II sulfate and sodium hydroxide are iron II hydroxide and sodium sulfate. The balanced chemical equation for this reaction is FeSO4 + 2NaOH → Fe(OH)2 + Na2SO4.
dark green (but orange - brown if left standing)
Fe(OH)2 is named iron(II) hydroxide. It can also be named ferrous hydroxide.