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What is the acceleration of a 20 kg pail of cement that is pulled upward with a force of 400 n?
Wiki User
∙ 10y ago
Gravitational pull on the pail = 20 [kg] * 9.8 [m / s2].
Net force upward = 300 [N] - 20 [kg] * 9.8 [m / s2] = 104 [N].
(recall that 1 [N] = 1 [kg] * 1 [m / s2])
Mass, M = 20 [kg]
By Newton's 2nd law of motion, F = M * A.
upward acceleration, A = F / M = 104 [N] / 20 [kg] = 5.2 [m/s2].
Wiki User
∙ 14y ago
Wiki User
∙ 10y agoIts downward weight is 20 x 9.8 Newtons, or 196 Newtons, so the net force is 400-196 or 204 N, so the upward acceleration is 204/20metres/second2 or 10.2 m/s2.
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