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What is the acceleration of a vehicle that changes its velocity from 80 km h to a dead stop in 13 s?
Wiki User
∙ 14y ago
As velocity is reduced, acceleration is negative.
Acceleration = change in velocity / time taken
Velocity is m/second is got by multiplying 80 km p h by a fraction 5/18 which gives 200/9
m/s
200/9 is divided by 13s would give the required acceleration. That equals 1.7094 m/s2
So the retardation is 1.7094 m/s2
Wiki User
∙ 14y ago
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What is the acceleration of a vehicle that changes velocity from 100km to a dead stop in 30seconds?
It wont be accelerating at all, its in the process of stopping you ignorant sh it
What is the acceleration of a vehicle that changes its velocity from 500 kmh to a dead stop in 20 s?
v=u+(a*t) 0=500+(a*20) (0-500)/20=a a=-25(km/h)/s
Is A steep slope on a displacement vs. time graph indicates a large velocity.?
Not necessarily. The slope could be steep but negative, and since negative numbers are less than positive numbers, no. But in both cases, the magnitude of the velocity (speed) is great. Also, at each point in the displacement vs. time graph, you can only get instantaneous velocity. A curve on the graph will indicate an acceleration. The next antiderivative of acceleration is jerk. According to the Heisenberg uncertainty principle, the more certain you are of a particle's position OR velocity, the less certain you can be of the other property. On the displacement vs. time graph, either the particle is at a certain displacement and the velocity unknown, or the velocity between two points is known, but the displacement is unknown. That is, the velocity can be known between two points, but the particle resides somewhere between the two points at that time. The exact position is uncertain. Schroedinger had a cat. He put it in a box, and having no way to tell if the cat was alive or dead, it must be assumed to be both, simultaneously. But also because it is either alive or dead, and not both at once, yet also not partially one or the other, it must be assumed to also be neither at once. So Schroedinger's cat was both alive and dead, though it was neither. By corollary, the particle whose trajectory is described by the displacement vs. time graph has no velocity and has velocity at the same time.
Is steep slope on a displacement vs. time graph indicates a large velocity.?
It means a large acceleration, i.e. forward speed rapidly increasing or decreasing, or backward speed rapidly increasing. Note: It's really not possible to present a velocity-vs-time graph in any simple way. What you're looking at is a speed-vs-time graph.
Can you answer show work A hockey puck is sliding along the ice with a constant velocity of 6 m s Its mass is 0 point 5 kg What force must be applied to bring the puck to a complete stop in 2 seconds?
That's the basic calculation: V0 - the starting velocity/speed (m/s) a - acceleration (m/s) t - duration of the acceleration (s) v=v0+a*t in this case if the puck wasn't moving and you have accelareted it for 2 seconds v=0+6*2=12 (m/s) If I missunderstood your question then let me apologize for it.......
What is the acceleration of a vehicle that changes velocity from 100km to a dead stop in 30seconds?
It wont be accelerating at all, its in the process of stopping you ignorant sh it
What is the acceleration of a vehicle that changes its velocity from 500 kmh to a dead stop in 20 s?
v=u+(a*t) 0=500+(a*20) (0-500)/20=a a=-25(km/h)/s
Is A steep slope on a displacement vs. time graph indicates a large velocity.?
Not necessarily. The slope could be steep but negative, and since negative numbers are less than positive numbers, no. But in both cases, the magnitude of the velocity (speed) is great. Also, at each point in the displacement vs. time graph, you can only get instantaneous velocity. A curve on the graph will indicate an acceleration. The next antiderivative of acceleration is jerk. According to the Heisenberg uncertainty principle, the more certain you are of a particle's position OR velocity, the less certain you can be of the other property. On the displacement vs. time graph, either the particle is at a certain displacement and the velocity unknown, or the velocity between two points is known, but the displacement is unknown. That is, the velocity can be known between two points, but the particle resides somewhere between the two points at that time. The exact position is uncertain. Schroedinger had a cat. He put it in a box, and having no way to tell if the cat was alive or dead, it must be assumed to be both, simultaneously. But also because it is either alive or dead, and not both at once, yet also not partially one or the other, it must be assumed to also be neither at once. So Schroedinger's cat was both alive and dead, though it was neither. By corollary, the particle whose trajectory is described by the displacement vs. time graph has no velocity and has velocity at the same time.
Is steep slope on a displacement vs. time graph indicates a large velocity.?
It means a large acceleration, i.e. forward speed rapidly increasing or decreasing, or backward speed rapidly increasing. Note: It's really not possible to present a velocity-vs-time graph in any simple way. What you're looking at is a speed-vs-time graph.
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