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the force acting down the slope = sin 30 * 25 (kg) = 0.5 * 25 = 12.5 kg = (12.5 * 9.806 ) 122.575 newtons = resultant force of (122.575-120 ) 2.575 newtons downhill giving downhill acceleration of (using f=ma) 0.103 (m/s)/s

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Q: What is the acceleration of the 25 kg crate which is pulled by a rope along a frictionless surface at an angle of 30 degrees above the horizontal if the tension on the rope is 120 N?
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Can acceleration happen on a frictionless surface?

yes


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