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Can a body have constant acceleration and zero velocity?
Since the derivative of velocity is acceleration, the answer would be technically 'no'. Here is why: v = 0 v' = 0 = a Or in variable form... v(x) = x v(0) = 0 v'(0) = 0 = a You can "trick" the derivative into saying that v'(x) = 1 = a (since the derivative of x = 1) and then stating v'(0) = 1 = a... but that is not entirely correct. Acceleration is a change over time and is measured at more then one point (i.e. the acceleration of this body of matter is y from time 1 to 5) unless using derivatives to form the equation of the acceleration line/curve. If an object has a constant acceleration of 1, then the velocity is constantly increasing over that time. Using the equation discussed above and looking at acceleration over time, at 0 seconds, acceleration is 0 and so is velocity, but from 0-1 seconds acceleration is 1 and velocity is 1 as well. 0-2 seconds, acceleration is 1, but velocity would be 2 (at the end of 2 seconds).
What is the velocity of the ball 0.6 seconds after its release?
Assuming you release it from a position of rest, you must multiply the time by the acceleration. The acceleration due to gravity near Earth's surface is approximately 9.8 meters/second squared.
A ball starts at rest accelerates uniformly and travels 250m in 5 seconds What is the final velocity and the acceleration of the ball?
Average speed = (250 / 5) = 50 meters per second.Initial speed = 0Final speed = 100 m/sAcceleration = (100 / 5) = 20 m/s2===> Must be a rocket-propelled ball; its acceleration is 2G !
What force would be needed to produce an acceleration of 1 ms-2 on a ball of mass 1 kg?
1N
What is the acceleration from 0 to 2s?
-- Its magnitude is 1/2 of [ (the speed at 2 seconds) minus (the speed at zero) ]. -- Its direction is 1/2 of [ (the direction at 2 seconds) minus (the direction at zero) ].
After 2 seconds its velocity is 9 meters per second what is the accleration of a ball?
If the ball started off stationary and the acceleration is the same for the 2 seconds, then the acceleration of the ball is:Speed / time = acceleration9 (m/s) / 2 (s) = 4.5 (m/s/s)Hope this helps.
Can a body have constant acceleration and zero velocity?
Since the derivative of velocity is acceleration, the answer would be technically 'no'. Here is why: v = 0 v' = 0 = a Or in variable form... v(x) = x v(0) = 0 v'(0) = 0 = a You can "trick" the derivative into saying that v'(x) = 1 = a (since the derivative of x = 1) and then stating v'(0) = 1 = a... but that is not entirely correct. Acceleration is a change over time and is measured at more then one point (i.e. the acceleration of this body of matter is y from time 1 to 5) unless using derivatives to form the equation of the acceleration line/curve. If an object has a constant acceleration of 1, then the velocity is constantly increasing over that time. Using the equation discussed above and looking at acceleration over time, at 0 seconds, acceleration is 0 and so is velocity, but from 0-1 seconds acceleration is 1 and velocity is 1 as well. 0-2 seconds, acceleration is 1, but velocity would be 2 (at the end of 2 seconds).
What is the velocity of the ball 0.6 seconds after its release?
Assuming you release it from a position of rest, you must multiply the time by the acceleration. The acceleration due to gravity near Earth's surface is approximately 9.8 meters/second squared.
What is the acceleration from 9 seconds to 12 seconds explain?
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A ball starts at rest accelerates uniformly and travels 250m in 5 seconds What is the final velocity and the acceleration of the ball?
Average speed = (250 / 5) = 50 meters per second.Initial speed = 0Final speed = 100 m/sAcceleration = (100 / 5) = 20 m/s2===> Must be a rocket-propelled ball; its acceleration is 2G !
What will the velocity and acceleration be of a ball at its highest trajectory point just before it starts to fall?
The acceleration of the ball (after it leaves the thrower's hand) is the acceleration due to gravity, g.1 The vertical velocity of the ball at its apex is zero. The horizontal velocity is constant throughout the ball's flight; it is whatever it was at the outset of its arc.2 ---------------- 1. The acceleration due to gravity, g, is -9.8 m/s2 or -32.2 ft/s2. 2. Ignoring the effects of air resistance, which tend to slow things down.
What force would be needed to produce an acceleration of 1 ms-2 on a ball of mass 1 kg?
1N
What is the acceleration experienced by a car that takes 10 seconds to reach 27 meters per seconds from rest?
velocity = acceleration x time 27 = acceleration x 10 acceleration = 2.7 m/sec/sec
What is the acceleration from 0 to 2s?
-- Its magnitude is 1/2 of [ (the speed at 2 seconds) minus (the speed at zero) ]. -- Its direction is 1/2 of [ (the direction at 2 seconds) minus (the direction at zero) ].
A rolling ball has an initial velocity of 5 meters per second 30 seconds later its velocity is 2 meters per second What is the acceleration of the ball?
The acceleration of the ball can be easily found using the kinematic equation if = vi + at. Where vi = initial velocity, if = final velocity, a = acceleration, and t = seconds. The acceleration is -0.1 m/s^2.
What is the speed and acceleration of a ball rolling down a hill?
The acceleration of a tennis ball rolling down an incline depends with two factors. The force that is applied to the tennis ball and the mass of the tennis ball will determine its acceleration.
A car accelerates from a standstill to 60 kmhr in 10 seconds What is its acceleration?
A car accelerates from a standstill to 60km/hr in 10.0 seconds what is its acceleration
