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What is the acceleration of the boat for the 2 s to 4 s time interval?
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How do you calculate distance traveled with force mass and time?
Time, velocity and mass do not provide enough information. If you are given a time interval, t, then you need the velocity at the start of the interval (= u) and at its end (v). Then F = m*(v - u)/t
Formula for accleration?
There are several formulae that involve acceleration. The most basic one is the definition of acceleration, which is: a = (difference in velocity) / time This assumes constant acceleration. For non-constant acceleration, the more general formula is: a = dv / dt where "dv" is the difference in velocity, and "dt" is the time interval, with the additional assumption that it is a very small time interval. For more details, read an introductory calculus book, to understand the concept of "derivative".
Find the time interval of acceleration?
You want to take your change in velocity(Final Velocity - Initial Velocity)(Vi - Vf) (8.3 m/s - 5.0 m/s = 3.3m/s). The, you divide it by your average acceleration (0.50 m/s^2) (3.3m/s ÷ 0.50 m/s^2 = 6.6 m/s) So the Final Formula is t =(Vf - Vi) ÷ a
Is time dialation exponential or linear?
Time dilation, which can be derived from the Lorentz transformations is t'=t/sqrt(1-v^2/c^2) where t is the time interval in the rest frame, and t' is the interval in the lab frame. This relationship is neither linear or exponential in v.
Who. A distance-time graph indicates that an object travels 2 m in 2 s and then travels another 80 m during the next 40 s. What is the average speed of the object?
Answer: The average speed of the object is 1.95 m/s. Explanation: Distance traveled by an object in the first interval, = 2 m Time is taken in firsts interval = 2 s Distance traveled by an object in the second interval, = 80 mm Time taken in second interval = 40 s The average speed of the object is 1.95 m/s.
How do you calculate distance traveled with force mass and time?
Time, velocity and mass do not provide enough information. If you are given a time interval, t, then you need the velocity at the start of the interval (= u) and at its end (v). Then F = m*(v - u)/t
Formula for accleration?
There are several formulae that involve acceleration. The most basic one is the definition of acceleration, which is: a = (difference in velocity) / time This assumes constant acceleration. For non-constant acceleration, the more general formula is: a = dv / dt where "dv" is the difference in velocity, and "dt" is the time interval, with the additional assumption that it is a very small time interval. For more details, read an introductory calculus book, to understand the concept of "derivative".
How do you find time when given distance and acceleration?
Distance = (1/2 of acceleration) x (time squared)You can change this around to solve it for acceleration or time.(Time squared) = (distance)/(half of acceleration)Time = the square root of [ (2 x distance)/(acceleration) ]Be careful . . .This is only true if the distance and the speed are both zero when the time begins.
If the speed of an object changes from 121ms to 98 ms during a time interval of 12s what is the acceleration of the object?
Acceleration is equal to the change in velocity over the change in time [a=(vf-vi)/(tf-ti). a=(98m/s - 121 m/s)/(12s)=(-23m/s)/(12s)=-1.92m/s^2
What is the acceleration on a distance time graph measured in?
Acceleration has a dimensionality of length/time^2, so if you were measuring the distance in meters and the time in seconds, the acceleration would be m/s^2.
How do you calculate acceleration from velocity?
There are 3 formula 1. Final velocity = starting velocity + (acceleration)(time) 2. Final velocity^2 = starting velocity^2 + 2(acceleration)(distance) 3. Distance = (starting velocity)(time) + 1/2(acceleration)(time^2) Use whichever you can use.
Find the time interval of acceleration?
You want to take your change in velocity(Final Velocity - Initial Velocity)(Vi - Vf) (8.3 m/s - 5.0 m/s = 3.3m/s). The, you divide it by your average acceleration (0.50 m/s^2) (3.3m/s ÷ 0.50 m/s^2 = 6.6 m/s) So the Final Formula is t =(Vf - Vi) ÷ a
What is dive tank?
diver's short name or code for your 'average' dive trip on a dive boat - 2 dives, each separated by an approximate 1 hour SIT (Surface Interval Time), usually on 2 different dive spots.
When is acceleration constant?
We have constant acceleration all the time. Its called gravity. Gravitational acceleration is 9.8... m/s^2
What is a two-tank dive?
diver's short name or code for your 'average' dive trip on a dive boat - 2 dives, each separated by an approximate 1 hour SIT (Surface Interval Time), usually on 2 different dive spots.
When will you say a body is in 1 uniform acceleration 2 non uniform acceleration?
Uniform acceleration means that the acceleration doesn't change over the course of time (of the time considered for a certain problem, at least).
What is the acceleration equation using acceleration force of gravity and velocity?
s = ut + 1/2 at^2 s=displacement u= initial velocity t=time a=acceleration
