The mass of the object doesn't matter, but the answer does depend on the angle (steepness) of the ramp.
That's an "idealized" pendulum, which is completely rigid, and where all the mass is concentrated in the bob, which is considered to be pointlike.
A hockey puck of mass m = 0.25 kg is tied to a string and is rotating horizontally in a circle of radius R = 1.0 m on top of a frictionless table.
In free fall an object regardless of its mass will accelerate at 9.8 meters/second/second or 32 feet/second/second assuming that you are on earth in a frictionless environment. This means that any two objects regardless of their mass will fall to the ground at the same rate.
your mass is still the same
The car's mass should have no effect on that speed.
A 9.4kg mass is attached to a light cord that passes over a massless frictionless pulley. The other end of the cord is attached to a 3.2kg mass. The final speed after mass 1 falls 4.5m is approximately 6.6 meter per square second.
Fx=G*sin(t) = m*g*sin(t) a=Fx/m=g*sin(t) ->> does not depend on mass
That's an "idealized" pendulum, which is completely rigid, and where all the mass is concentrated in the bob, which is considered to be pointlike.
Use the equation vf^2-vi^2/2a=h vf=2.2 vi=0 a=9.8 because of gravity so the answer is .247
Work: don't care about time (that's power) frictionless means don't care about length of plane only care about height and mass -- figure 9.8 m/s*s for acceleration of gravity F=ma F times distance (up) = work good luck
You have to get rid of mass. Throw things, spit, fire a gun if you have one, etc. Since momentum is conserved, every time you get rid of something, you move across the ice in the opposite direction.
A hockey puck of mass m = 0.25 kg is tied to a string and is rotating horizontally in a circle of radius R = 1.0 m on top of a frictionless table.
When an object is dropped near the Earth's surface, and it experiences no air resistance, then its speed after 3 seconds is 29.4 meters (96.5 feet) per second, and its velocity is directed toward the Earth's center of mass, nominally the Earth's geometric center, colloquially referred to in the bourgoise vernacular as "down".
Newtons second Law: Force applied on a body is directly proportional to the rate of change of momentum of the body or mass times acceleration (when proper units are chosen, (F = ma). If you change the mass of an object on a (frictionless) surface and apply a constant force the body will acellerate differently. The Mass: a bunch of identiacl items that you can count (metal nuts) in a container with a flat (plastic bottom) Frictionless surface: Flat (wet) glass Force: a spring or rubberband you pull out to a given length befor letting the mass go. Acelleration (stroboscopic photograph, "ticker tape" with constant period marking dots on a paper ribbon... the experiment: Measure the acelleration with mass#1. Repart with twice, three times, four times the mass. Result: Plot the results on log graph paper.
The atomic mass increases down a group.
A block of mass M is pulled with a rope on a frictionless surface If a force P is applied at the free end of the rope what will be the force exerted by the rope on the block if the mass of rope is m? Equation#1: Force = mass * acceleration The force P pulls a total mass of (M + m) accelerating both masses at the same rate. Equation #2: P = (M + m) * a Equation #3: a = P ÷ (M + m) At the point where the rope is attached to the block, the block of mass M feels a force making it accelerate at a rate of a = P ÷ (M + m). The force required to make at block of mass M accelerate at a rate of a = P ÷ (M + m) can be determined by equation #4. Equation #4: F of block = mass of block * [P ÷ (M + m)].
The mass of reactants is equal to the mass of products.