There is no 'active' power in a purely capacitive load. Active power is the result of the supply voltage multiplied by the in-phase component of the load current. In a purely capacitive load, the load current leads the supply voltage by 90 degrees and, so, there is no in-phase component and, hence, no active power.
Power = Watts = Volts x Amps x Power Factor.
Power Factor is 1 for resistive load and decreases with inductive loads. Power Factor is essentially related to the difference in phase between the voltage and current waveforms. The bigger the phase difference, the smaller the power factor. If they are 180 degrees out of phase no power is delivered.
AnswerA purely-inductive load has no resistance. Therefore, the load current lags the suppy voltage by 90 degrees -giving a power factor of 0.
Since P = V I x power factor, it is clear that no active power is supplied.
(Further to the original answer, the current through a pure inductance cannot be 180 degrees out of phase with the supply voltage!)
For maximum power transfer, source resistance should match load resistance and source reactance should match load reactance with the opposite sign (so if the load is capacitive, the source should be inductive).
I believe you're referring to reactive power. Reactive power is present any time the voltage and current are AC signals and not in phase. Some current simply charges and discharges the load reactance, and therefore does not deliver real power to the load.
The power consumed in an AC circuit becomes zero when the voltage and current are in phase with each other. This means that the voltage and current waveforms reach their maximum and minimum values at the same time, resulting in a power factor of 1. In this case, the power consumed by the circuit is purely reactive and does not contribute to any real power dissipation.
A lagging power factor is caused by inductive reactance, which is composed of resistance and inductance -- and the resistance component lowers the supply volts. A leading power factor provides capacitive reactance that actually helps improve source voltage -- this helps motor loads run cooler.
If the load on an AC system is purely resistive, then the voltage and current waveforms will be in phase. A desirable state. When the load has some reactance, then these two parts of the power signal will not be in phase; and this results in an inferior power generation, in which some of the work needed to generate the signal is not available as real work at the terminus. This undesirable condition occurs with both inductive loads such as electric motors, and capacitive loads, such as fluorescent lighting. This may be corrected for in real-life systems by employing 'power factor' correcting equipment. One common device is the 'rotary capacitor' - in reality, a rotating transformer in which the phase is controlled as to make it appear as a capacitor, not as an inductor. Ordinary transformers transfer the reactance of their load, with a small percentage of genuine reactance due to hysteresis losses in the core of the transformer.
There is pure resistance, inductive reactance, and capacitive reactance.
by adding the opposite type of reactance. as motors are a common industrial load and their reactance is inductive, add capacitive reactance.
Capacitive loads have a leading power factor. Current leads voltage when there is capacitive reactance. (The opposite is inductive, which is lagging.)
No power is dissipated by a load composed exclusively of either capacitive or inductive reactance.
VAr is reactive power, caused by either inductive or capacitive loads. The ideal power factor to have is 1, anything less than that is a loss on the network. The effect of VArs on the circuit though depends. If you have a load that is mainly inductive, then adding more inductive reactance will lower the power factor. However, if you introduce capacitive reactance this will increase the power factor, and the opposite is true if its a mainly capacitive circuit. So VArs will either increase or decrease the power factor depending on the load of the circuit. The ideal situation is to balance inductive reactance with capacitive reactance so they in effect cancel each other out and power factor is 1.
The active power of an inductor is zero. As we know, the active power is the result of product of supply voltage and in-phase component of load current. But the load current in pure inductive load lags supply voltage by 90 degrees. So there is no component of load current that is in-phase with the supply voltage. Therefore, the active power in inductive reactance is zero.
No. It depends on the inductive and capacitive reactance of the load.
yesAnswerNo, but you can counter its effects. For example, if your load is inductive, then you can counter the effects of its inductive reactance by introducing capacitors with equal capacitive reactance.
current - movement of electrical chargesvoltage - electrical force/pressurepower - work doneresistance - opposition to currentinductive reactance - opposition to changes in currentcapacitive reactance - opposition to changes in voltagetotal impedance - vector sum of resistance, inductive reactance, and capacitive reactanceetc.
When the power factor is 1, that is neither capacitive or inductive, the load does not have reactance that impedes current flow. Power companies like that.
== == Add a capacitor or a synchronous motor or a phase advancer to the transmission line so that it can nullify the effect of inductive reactance since the above elements gives capacitive reactance. Doing this also improves the power factor.
Wattmeters are not used for loads which are purely capacitive or inductive, because no watts are consumed and no energy is consumed by the customer. But amps must still be supplied by the power company to supply the customer's capacitive or inductive load and the result is measured in volt-amps reactive (VAR), which can be registered on a meter called a reactive power meter. The ratio of watts to volt-amps is called the power factor (a capacitive load has a power factor close to zero). Industrial customers with a poor power factor are penalised with higher tariffs and encouraged to improve their power factor.