The standard atmosphere (symbol: atm) is a unit of pressure and is defined as being precisely equal to 101.325 kPa Air Density decreases at a rate of 2.9% - 3.0% for each 1000 ft. of elevation above Sea Level. See Standard Atmosphere below for background information. 1 000 feet = 304.8 meters So in rough terms You will lose about 1% of the pressure for each 100 meters due to elevation increase 0m = 101.325 100m =101.32500 - (101.32500 * .01) = 100.31175 200m = 101.32500 - (101.32500 * .02) = 99.2985
1,000 millibars is - 0 altitude
200 millibars is- 10 altitude
Convention sets it at 1 mb at the top, and generally about 50-90 mb at the bottom.
The troposphere is the lowest layer of the earth's atmosphere and is the one that contains weather and which can support life. Its upper limit is the highest point that the suns heat can cause warm and moist air to reach. This means that the troposphere extends to a much higher altitude in the tropics than near the cooler poles - between 15km (9 miles) to 8km (5 miles). Atmospheric pressure varies from around 1000 kpa (14 pounds per square inch, PSI) at sea level down to about 200 kpa (3psi) at about 10km.
He's blood pressure has to reach to 200.
An approximate value can be calculated by the following expression: Condensation Level (in feet) = [Surface Temperature(F) - Surface Dew Point Temperature(F)]*(1000/2.2) or Condensation Level (in meters) = [Surface Temperature(C) - Surface Dew Point Temperature(C)]*(200) Solution: Dry Adiabatic Lapse Rate (DALR) => -5.5 F/1000 ft of altitude (-1C/100m) Saturated Adiabatic Lapse Rate (SALR) => -3.3F/1000ft of altitude (-0.5C/100m) The SALR is not linear and varies with the initial surface temperature The Level of Condensation will occur at the altitude where the Air Temperature is equal to the Dew Point temperature at that altitude. Setting the two equations equal to each other will give an approximate value. TA: temperature at altitude; TS: temperature at surface; DA: dew point temperature at altitude; DS: dew point temperature at surface TA = TS-(5.5F/1000ft)*altitude or TS-(1C/100m)*altitude DA = DS-(3.3F/1000ft)*altitude or DS-(0.5C/100m)*altitude Setting TA = DA and rearranging quantities gives the equations given above The level of condensation derived by the above method will only yield an approximate value.
200 meters
Convention sets it at 1 mb at the top, and generally about 50-90 mb at the bottom.
First, determine the difference from standard pressure 29.92. 30.12 -29.92 --------- .20 If you drop the decimal point and add a zero you get the number of feet of difference, so .20 = 200 feet. Since 30.12 is a higher number than 29.92, you subtract it from the actual altitude. If the indicated altitude is 10000 feet, your pressure altitude is 9800 feet. If your altimeter setting is lower than 29.92 you add the difference. It can also be expressed as PA = IA + ((29.92 - AS) * 1000) where IA is indicated altitude and AS = altimeter setting.
First, determine the difference from standard pressure 29.92. 30.12 -29.92 --------- .20 If you drop the decimal point and add a zero you get the number of feet of difference, so .20 = 200 feet. Since 30.12 is a higher number than 29.92, you subtract it from the actual altitude. If the indicated altitude is 10000 feet, your pressure altitude is 9800 feet. If your altimeter setting is lower than 29.92 you add the difference. It can also be expressed as PA = IA + ((29.92 - AS) * 1000) where IA is indicated altitude and AS = altimeter setting.
No, 200 is a factor of 1000.
Air has weight, and weight means pressure. The higher up you go, the less air left above to press down --and so, less pressureAir Pressure decreases with the rise of altitude and increases when lowered. Example: You would not be able to breathe as well high in the air as you would standing on the ground.At higher altitude, air pressure decreases. Eventually the air runs out entirely at about 200 miles altitude, at which point you are in outer space with zero air pressure.Air pressure drops at higher altitudes. This makes water boil at a lower temperature, causing difficulties in cooking and makes it harder for people to get their breath.This is also why commercial airplanes are pressurized inside.Air pressure declines with altitude (becoming effectively zero at about 200 miles in altitiude). That is because air pressure is the result of the weight of the air, and the higher you go, the less air you have above you to press downward and cause air pressure.As altitude increase air pressure decrease.Air pressure is a result of the total weight of the all the air (or column of air) from above as well as the sideways pressure from the weight pressing down on the air around the current position. As the altitude increases, their is less air pressing down from above (and from above the surrounding area) so the air pressure decreases as the altitude increases.
In my opinion, 200 feet of altitude, either higher or lower, from the normal baseline altitude of the person, will have little to no affect on breathing or pulse.
800
The product is 200
20 percent of 1000 = 200 20% of 1000 = 20% * 1000 = 20%/100% * 1000 = 200
The tangent of 4 degrees would be equal to x/200, where x is the altitude in feet. tan(5) = x/200 tan(5)*200 = x x is about 17.4977, so, if you started at 0 feet, your altitude would be about 17.4977 feet.
Not sure what your asking here. 1000/200 = 5
20% of 1000 is 200 therefore: 1000 + 200 = 1200