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They require the same amount of work because the formula for work is force times distance.
It depends on the distance over which the work is done. Work = Force x distance
Work is done in lifting is equal to work done in opposing gravity. Work done in opposing gravity = weight times distance = 700 x 4 =2800 joules
Force • distance
The same type as is done when pushing, shoving, rolling, lifting, wiggling etc. ... a force acting through a distance.
They require the same amount of work because the formula for work is force times distance.
By increasing the distance also increasing the amount of work done
It depends on the distance over which the work is done. Work = Force x distance
Work = force x distance.
Work is done in lifting is equal to work done in opposing gravity. Work done in opposing gravity = weight times distance = 700 x 4 =2800 joules
Force • distance
There are two factors on which work done depends. 1:- Force2:- Distance or displacement
The same type as is done when pushing, shoving, rolling, lifting, wiggling etc. ... a force acting through a distance.
Assuming 100% efficiency, the amount of work depends on the weight and the vertical distance (that is, opposite to the pull of gravity) moved. If you use a ramp then you reduce the force by an amount k, that's true, but the distance you have to push in the direction of the force is multiplied by k. The work done is [original force]/k times [vertical distance]times k and the k cancels out. For vertical lifting k=1.
6 m
Work = (force) x (distance). Time is not involved.But if that amount of work was done in that amount of time, then(force) x (distance)/(time) is the average power during that time.
No. If you are, say, lifting a weight the amount of work done is the same whether you use a pulley or not. However, you may not be able to actually lift the weight unless you use a pulley. But the amount of work done will be the same with or without the pulley.