90 degrees
2pi/3 radian or equivalent 120 degree
When b is zero.
The magnitude of a vector is always treated as non negative and the minus sign indicates the reversal of that vector through an angle of 180 degree.
If two lines have angles theta1 and theta2 relative to some third arbitrary line, then the angle between those two lines is theta1 minus theta2. The normal of a line at a point is a line that is 90 degrees from the line going through that point, so the angle between a line and its normal is 90 degrees. As a result, the angle between the two normals of those lines is (theta1 plus 90) minus (theta2 plus 90), which is the same as theta1 minus theta2 because the two plus 90's cancel each other.
The Resultant Vector minus the other vector
The third angle of a triangle is equal to 180 degrees minus (the sum of the first two angles).
45o This is because 90 minus 45 is 45.
It means that the angle in question is any multiple of 180 degrees.
The question is not correct, because the product of any two vectors is just a number, while when you subtract to vectors the result is also a vector. So you can't compare two different things...
A supplementary angle is a 180-degree angle minus the number of degrees in the given angle.
Yes. For example, if one vector has a length of 1 and points north, and the second vector has a length of 1 and points south, the difference (vector1 minus vector2) will have a length of 2 and point north.
No. An angle is (90 minus its complement) degrees. The definition of the complement is "90 degrees minus the original angle".