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The principal range of arc tan is an angle in the open interval (-pi/2, pi/2) radians = (-90, 90) degrees.
No domain no range
The range of -sin x depends on the domain of x. If the domain of x is unrestricted then the range of y is [-1, 1].
The range of the circular trig functions sin and cos is is [-1,1], but even in the case of circular functions the range of the tangent function is all real numbers. This is of course true of tangent even if we do not limit it to circular functions. So your question, I assume, is asking about all trig functions. If so the range is all real numbers.
The range for high triglycerides is 200-499. Borderline-high triglycerides can be anywhere from 150 to 199, so your 'severity' depends on how far you are into that bracket.
45 degrees.
15.42 degrees
The range of projectile is maximum when the angle of projection is 45 Degrees.
"the higher the altitude the lower the range "
Without considering any effects of air resistance and wind, the angle of projection that delivers the greatest horizontal range is 45 degrees above the horizon. Anything different ... either more or less than 45 degrees ... reduces the range.
You cannot. You need to know either the initial speed or angle of projection (A).
A stone is thrown with an angle of 530 to the horizontal with an initial velocity of 20 m/s, assume g=10 m/s2. Calculate: a) The time it will stay in the air? b) How far will the stone travel before it hits the ground (the range)? c) What will be the maximum height the stone will reach?
If you are looking to get an object up the highest, shoot it straight up. If you want to go for a specific horizontal displacement, use the range equation. R = v2sin(twice the launch angle)/ g. g is the gravitaional constant, 9.8 meters per second. Use degrees for the angle. v is the launch velocity. R is the horizontal displacement. This formula only works if your start altitude and end altitude are the same, i.e. you must shoot over a level field.
The more elevated the launcher is the shorter the range of the launcher to the ball. Hope it helps :)
w2hen the angle of projection is larger than 45 degree the height attained will be more but the range is again less.in this case angle is 30 degree which is less than 45 degree and 60 degree angle is greater than angle of 45 degree which have less range and is equal to range of 30 degree .so ranges are equal.
If a shell is fired from the ground with velocity of 1600 m and an angle of 64 to the horizontal then it would have a horizontal rang of 55.0. This is considered math.
At a certain angle - 45 degrees if the starting point and end point are at the same level, and air resistance can be ignored - and at a certain speed, the range is maximum. Both for lower and for higher angles, you get a lower range.