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Q: What is the answer for x2 xx-5-x 7?
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What is the factor of X4 plus X2 - 42?

x4 + x2 - 42 Let x2 = t, so that x4 = t2 t2 + t - 42 since -42 = 7(-6) and 7 + (-6) = 1, then t2 + t - 42 = (t - 6)(t + 7) = (x2 - 6)(x2 + 7) By replacing t with x2. So we have, x4 + x2 - 42 = (x2 - 6)(x2 + 7) = [x2 - (square root of 6)2](x2 + 7) = (x - sq. root of 6 )(x + sq. root of 6)(x2 + 7)


X2 plus 7 equals 36?

if x2 + 7 = 37, then x2 = 29 and x = ±√29


What is the answer to x2-49 when you completely factor?

x2-49 = (x-7)(x+7)


What is x2 plus 49?

x2 + 49 = x2 - (-49) = x2 - (-1)(49) = x2 - (i2)(72) = x2 - (7i)2 = (x - 7i)(x + 7i) where i is the imaginary square root of -1.


What is the quadratic function of x2 plus 6x-7?

x2+6x-7 = (x+7)(x-1) when factored


How do you factor -x2 plus x plus 42?

-x2 + x + 42 = -[x2 - x - 42] = -[x2 - 7x + 6x - 42] = -[x*(x - 7) + 6*(x - 7)] = -(x - 7)*(x + 6)


How do you Factor x2-14x plus 49?

x2 - 14x + 49(x - 7) (x - 7)


What is x2 - 9?

-7


X2 plus 2x plus -6 equals 0?

x2 + 2x -6 = 0 x2 + 2x + 1 = 7 (x + 1)2 = 7 x = -1 ± √7


How do you swap two numbers without third variables?

If the variables are x1 & x2 the solution is : 1) x1=x1+x2; 2) x2=x1-x2; 3) x1=x1-x2; EX: x1=1 , x2=6; 1) x1= 1+6 = 7 2) x2= 7-6 =1 3 x1=7-1 =6 ============================================


What is the Factor x2 plus 2x 63?

x2+2x-63 = (x-7)(x+9) when factored


What number must you add to complete the square of x2 minus14 equals 7?

Since there are only terms in x2 and constants, but none in x, completing the square is not an option! x2 - 14 = 7 x2 = 21 and so x2 = sqrt(21)